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tino4ka555 [31]
3 years ago
9

What is the weight of the water that is displaced by a floating object compared to the weight of the object?

Chemistry
1 answer:
Serga [27]3 years ago
3 0

Answer:

The amount of fluid displaced is directly related (via Archimedes' principle) to its volume. In the case of an object that sinks (is totally submerged), the volume of the object is displaced. In the case of an object that floats, the amount of fluid displaced will be equal in weight to the displacing object.

Explanation:

wikipedia

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Answer:

pH = 8.92

Explanation:

To solve this question we must know that the reaction of KOH with HC3H5O2 is:

KOH + HC3H5O2 → H2O + KC3H5O2

At equivalence point, all propanoic acid reacts to produce KC3H5O2.

This KC3H5O2 = C3H5O2⁻ is in equilibrium in water as follows:

C3H5O2⁻(aq) + H₂O(l) → OH⁻(aq) + HC3H5O2(aq)

<em>Where Kb = Kw / ka = 1x10⁻¹⁴/ 1.34x10⁻⁵ = 7.46x10⁻¹⁰</em>

is defined as:

Kb = 7.46x10⁻¹⁰ = [OH⁻] [HC3H5O2] / [C3H5O2⁻]

As both [OH⁻] [HC3H5O2] ions comes from the same equilibrium,

[OH⁻] = [HC3H5O2] = X

[C3H5O2⁻] is:

<em>Moles KOH = Moles </em>C3H5O2⁻:

0.0325L * (0.15mol / L) = 0.004875 moles

In 32.5 + 20mL = 52.5mL = 0.0525L:

0.004875 moles / 0.0525L = 0.09286M.

Replacing:

7.46x10⁻¹⁰ = [X] [X] / [0.09286M]

6.927x10⁻¹¹ = X²

X = 8.323x10⁻⁶M = [OH-]

As pOH = -log [OH-]

pOH = 5.08

pH = 14 -pOH

<h3>pH = 8.92</h3>
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