Answer:
a) 81.5%
b) 95%
c) 75%
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 266 days
Standard Deviation, σ = 15 days
We are given that the distribution of length of human pregnancies is a bell shaped distribution that is a normal distribution.
Formula:
a) P(between 236 and 281 days)
b) a) P(last between 236 and 296)
c) If the data is not normally distributed.
Then, according to Chebyshev's theorem, at least 
data lies within k standard deviation of mean.
For k = 2
Atleast 75% of data lies within two standard deviation for a non normal data.
Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.
The first numerator is 3 and the second is 17 not 2
Answer:
31
Step-by-step explanation:
The Range is the difference between the lowest and highest values (3, 34)
If you change the point's x-coordinate, the point will move either to the left or the right, depending on if the number you change is negative or positive.
[~Answer~] (4.):
<em>Hello there! I'm Avery, and I'm here to help you! I mostly believe the answer </em><em>is 1 2/3
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++</em>
[~Answer Explanation~]:
First:
Convert any mixed numbers to fractions.
Reduce fractions where possible.
Then your initial equation becomes:
356÷72
Applying the fractions formula for division,
=35×26×7
=70/42
Simplifying 70/42, the answer is
=1 2/3
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
[~Last Messages~]:
Okay, I really hope my answer is correct.
I am truly sorry if it's wrong :(
Have a great morning, afternoon, or night. <333
[-!AveryIsSomeHowAlive!-]
