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jok3333 [9.3K]
3 years ago
12

Which structure is part of the inner ear?

Physics
2 answers:
ValentinkaMS [17]3 years ago
8 0

cochlea is part of the inner ear. have a great day my friend

Ulleksa [173]3 years ago
3 0

Answer:

Which structure is part of the inner ear?  

anvil  

eardrum  

ear canal  

<u>cochlea</u>

Hope this helps :)

Have a great day

5INGH

Explanation:

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Antireflection coatings can be used on the inner surfaces of eyeglasses to reduce the reflection of stray light into the eye, th
Basile [38]

Answer:

1.33

Explanation:

Using the formula for destructive interference since the two reflected ray light waves from eyeglass should be made to cancel each other ( destructive interference) and also refractive index of air less than the refractive index of the film and both are less than the refractive index of the glass meaning the both reflected rays from the air and film will experience a phase change

n film =  ( m + 0.5) ( λ / 2t)

since 2 t = ( m + 0.5) ( λ / n film)

where m is an integer, λ is wavelength, and t is thickness  and n film is the refractive index of film

for effectiveness m = 0

n film = ( 0.5) ( 480 ÷ (2 × 90 ) ) = 1.33

4 0
4 years ago
Two waves have the same frequency. What other characteristic must be the same for these waves?.
madreJ [45]

The wave characteristic that is the same for both waves is wavelength.

  • Two waves with the same frequency will also have the same wavelength, amplitude, speed, and period. When two waves are travelling at the same frequency, it denotes that their duration and amplitude are also the same.
  • When two waves of the same frequency and amplitude interfere constructively, their peaks and troughs align as shown in diagram A above. As a result, the original waves' amplitude is doubled, resulting in a sound wave that is twice as loud.

Thus, Equal frequencies are shared by two waves moving through the same region in the same direction.

To know more about wave

brainly.com/question/17076990

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4 0
1 year ago
A box of spherical jawbreaker candies is 23 g and its volume is 32.3 cm3. If the average mass of a single jawbreaker is 0.94 g,
Alex777 [14]

The radius of each jawbreaker is approximately 0.68 cm.

<h3>Volume of a sphere;</h3>
  • v = 4 /3 πr³

where

r = radius

Therefore,

23 g  = 32.3 cm³

0.94 g  = ?

cross multiply

volume of a single jawbreaker = 32.3 × 0.94 / 23 = 30.362 / 23 = 1.32 cm³

Therefore,

volume of each jawbreaker = 4 /3 πr³

1.32 = 4 / 3 × 3.14 × r³

r³ = 1.32 /4.18666666667

r³ = 0.31533683707

r = ∛0.31533683707

r = 0.680651651 = 0.68

Therefore, the radius of each jawbreaker is approximately 0.68 cm.

learn more on radius here: brainly.com/question/19172427

5 0
3 years ago
What is the strength of an electric field that will balance the weight of a 3.3 g plastic sphere that has been charged to -7.6 n
sp2606 [1]

As the plastic sphere is charged, therefore it experience an electric force when placed in an electric fields and also experiences gravitational force acts downward so the electric force must act upward.

Let  F_{E} is electric force and F_{G} is gravitational force.

If these forces are balanced, thereforeF_{E} = F_{G}

or                                                                      \left | q \right |E=mg\\\\\ E=\frac{mg}{\left | q \right |}

Given, q=-7.6 nC=-7.6\times10^{-9} C and  m=3.3 g= 3.3\times10^{-3} kg.

Substituting these values in above equation we get,

E=\frac{3.3\times10^{-3} kg\times9.8 m/s^{2} }{7.6\times10^{-9} C}\\\\E=4.2\times10^{6} N/C

Thus, the magnitude of electric field is 4.2\times10^{6} N/C.

As the charge is negative, the electric field at the location of the plastic sphere must be pointing downward.



8 0
3 years ago
A 18-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 30 N. Starting from rest, the sle
k0ka [10]

Answer:

Coefficient of kinetic friction = 0.146

Explanation:

Given:

Mass of sled (m) = 18 kg

Horizontal force (F) = 30 N

FInal speed (v) = 2 m/s

Distance (s) = 8.5 m

Find:

Coefficient of kinetic friction.

Computation:

Initial speed (u) = 0 m/s

v² - u² = 2as

2(8.5)a = 2² - 0²

a = 0.2352 m/s²

Nweton's law of :

F (net) = ma

30N - μf = 18 (0.2352)

30 - 4.2336 = μ(mg)

25.7664 =  μ(18)(9.8)

μ = 0.146

Coefficient of kinetic friction = 0.146

6 0
4 years ago
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