Decompose each velocity in its i and j - coordinates.
1) River's velocity
3.5 m/s, west fo east = 3.5i + 0j
2) Luke's velocity
5m/s, 60° east of north
5* sin(60°) i + 5*cos(60°) j = 4.33 i + 2.5 j
3) Resultant velocity
[3.5i + 0j] + [4.33i + 2.5j] = 7.83i + 2.5j
resultant speed = √[ (7.83)^2 + (2.5)^2 ] = 8.22 m/s
angle = arctan(2.5 / 7.83) = 17.7° north of east (equal to 72.3° east of north).
Answer:
c
Step-by-step explanation:
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Y = 2x² + 30x + 200
y = 2(x² + 15x + 100)
x² = x*x
100 ⇒ 1 x 100 ; 2 x 50 ; 4 x 25 ; 5 x 20 ; 10 x 10
200 = 2x² + 30x + 200
0 = 2x² + 30x + 200 - 200
0 = 2x² + 30x + 0
0 = 2(x² + 15x + ?)
<span>−5 ≤ x ≤ 20</span>
You answer is 229 multiply first then add (PEMDAS)
