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Salsk061 [2.6K]
2 years ago
5

A 4 L sample of gas at 298 K and 2 atm contains 0.250 mol of gas. If we add another 0.250 mol of gas at the same pressure and te

mperature, what is the final total volume of gas?
Chemistry
1 answer:
andrey2020 [161]2 years ago
4 0

Answer:

V_2=8L

Explanation:

Hello there!

In this case, considering the Avogadro's gas law, which treats the volume and moles in a directly proportional way via:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

Which can be solved for the final volume, V2, as shown below:

V_2=\frac{V_1n_2}{n_1}

Thus, by plugging in the given data, we obtain:

V_2=\frac{4L*(0.250mol+0.250mol)}{0.250mol}\\\\V_2=8L

Regards!

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Complex equation:

          Fe^{3+}+SCN^-\rightleftharpoons [Fe(SCN)]^{2+}

0.00075 M         0.1 M                        0

At equilibrium:

(0.00075 M -x)    (0.1 M-x)                  x

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