Answer:
3/8
Explanation:
Martha has a widow's peak (dominant trait) and attached earlobes (recessive trait).
Martha's dad had a straight hairline (ww) and unattached earlobes (Ee, because she has the recessive alleles ee and both parents give us one allele).
This tells you that martha has a mother with at least one of both alleles dominant for widow peak and at least one recesive allele of attached earlobes
So, martha's alleles are: Ww and ee.
If she marries a man that is heterozygous for both traits (Ww and Ee) the probabilitys are
Ww Ee x Ww ee: WWEe, WwEe, wWee, and wwee
Answer:
P = f(TLTL) = 0,16
H = f(TLTS) = 0,48
Q = f(TSTS) = 0,36
Explanation:
Hello!
The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).
The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.
In this case, let's say:
f(TL) = p
f(TS) = q
p + q = 1
Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:
TL= 0,4
TS= 0,6
Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.
P = f(TLTL)
H = f(TLTS)
Q = f(TSTS)
Also P + H + Q = 1
And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:



So, if the population is in balance:



Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:



I hope you have a SUPER day!
Answer:
I think it will be C (viewpoint)
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