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Licemer1 [7]
3 years ago
15

A fast camel travelled 180 miles in 4 hours and 156 miles in 3

Physics
1 answer:
maw [93]3 years ago
6 0
180+156=336
4+3=7
336/7=48mph
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A softball of mass 0.220 kg that is moving with a speed of 5.5 m/s (in the positive direction) collides head-on and elastically
Elanso [62]

Answer:

The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.

Explanation:

Given that,

Mass of softball = 0.220 kg

Speed = 5.5 m/s

(a). We need to calculate the velocity of the target ball

Using conservation of momentum

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

0.220\times5.5+m_{2}\times0=0.220\times(-3.9)+m_{2}v_{2}

1.21=-0.858+m_{2}v_{2}

m_{2}v_{2}=2.068....(I)

The velocity approach is equal to the separation of velocity

u_{1}-u_{2}=v_{2}-v_{1}

5.5-0=v_{2}-(-3.9)

v_{2}=1.6\ m/s

(b). We need to calculate the mass of the target ball

Now, Put the value of v₂ in equation (I)

m_{2}\times1.6=2.068

m_{2}=\dfrac{2.068}{1.6}

m_{2}=1.29\ kg

Hence, The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.

3 0
3 years ago
What is the mass of an object that requires 100n of force in order to accelerate it at 10m/s^2
Shkiper50 [21]
100.10= 1000

the formula is:

f=m/t
4 0
3 years ago
Read 2 more answers
If a car with an initial velocity of 10 m/s accelerates at a rate of 50 m/s^2
expeople1 [14]

Given:

Initial velocity (u) = 10 m/s

Acceleration (a) = 50 m/s²

Time taken (t) = 3 s

To Find:

Final velocity (v)

Answer:

By using equation of motion, we get:

\bf \longrightarrow v = u + at \\  \\  \rm \longrightarrow v  = 10 + 50 \times 3 \\  \\ \rm \longrightarrow v  = 10 + 150 \\  \\ \rm \longrightarrow v  = 160 \: m {s}^{ - 1}

\therefore Final velocity (v) = 160 m/s

6 0
3 years ago
Do only number 5 and thank
Naddik [55]

Answer:

Quantity of charge = 1800 Coulombs

Explanation:

Given the following data;

Current = 1 A

Time = 0.5 hours

Conversion:

1 hour = 60 * 60 = 3600 seconds

0.5 hour = 0.5 * 3600 = 1800 seconds

To find the charge passing through the wire;

Mathematically, the quantity of charge passing through a conductor is given by the formula;

Quantity of charge = current * time

Substituting into the formula, we have;

Quantity of charge = 1 * 1800

Quantity of charge = 1800 Coulombs

8 0
3 years ago
HELP MEE
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