Answer:
The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.
Explanation:
Given that,
Mass of softball = 0.220 kg
Speed = 5.5 m/s
(a). We need to calculate the velocity of the target ball
Using conservation of momentum



....(I)
The velocity approach is equal to the separation of velocity


(b). We need to calculate the mass of the target ball
Now, Put the value of v₂ in equation (I)



Hence, The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.
Given:
Initial velocity (u) = 10 m/s
Acceleration (a) = 50 m/s²
Time taken (t) = 3 s
To Find:
Final velocity (v)
Answer:
By using equation of motion, we get:

Final velocity (v) = 160 m/s
Answer:
Quantity of charge = 1800 Coulombs
Explanation:
Given the following data;
Current = 1 A
Time = 0.5 hours
Conversion:
1 hour = 60 * 60 = 3600 seconds
0.5 hour = 0.5 * 3600 = 1800 seconds
To find the charge passing through the wire;
Mathematically, the quantity of charge passing through a conductor is given by the formula;
Quantity of charge = current * time
Substituting into the formula, we have;
Quantity of charge = 1 * 1800
Quantity of charge = 1800 Coulombs
The interior structure of the Earth<span> is layered in spherical shells. These </span>layers<span> can be</span>defined<span> by their chemical and their rheological properties. </span>Earth<span> has an outer silicate solid crust, a highly viscous mantle, a liquid outer core that is much less viscous than the mantle, and a solid inner core.</span>