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Lapatulllka [165]
3 years ago
7

How do you calculate the mass of an object accelerating at22.35m/s2 with a force of 120N

Physics
1 answer:
Arte-miy333 [17]3 years ago
3 0

Answer:

The mass of object is calculated as 5.36 kg

Explanation:

The known terms to find the mass are:

           acceleration of object (a) = 22.35 m/s^{2}

                        Force exerted (F) = 120N

                        mass of an object (m) = ?

From Newton's second law of motion;

                                   F = ma

                           or, 120 = m × 22.35

                          or, m= \frac{120}{22.35} kg

                           ∴ m = 5.36 kg

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The Indianapolis Motor Speedway has four banked curves, each of which forms a quarter of a circle. Suppose a race car speeds alo
boyakko [2]

Answer:

r =  255.68 m

Explanation:

When a body moves in a circular path, an acceleration, due to constant change in its direction, is developed, known as centripetal acceleration. The centripetal acceleration acts towards the center of the circular path. The formula to calculate the centripetal acceleration is given as follows:

ac = v²/r

where,

ac = centripetal acceleration = 22 m/s²

v = tangential speed = 75 m/s

r = radius of curve = ?

Therefore,

22 m/s² = (75 m/s)²/r

r = (75 m/s)²/(22 m/s²)

<u>r =  255.68 m</u>

4 0
3 years ago
Measurements of how orbital speeds depend on distance from the center of our galaxy tell us that stars in the outskirts of the g
diamong [38]

Answer:

True

Explanation:

Measurements of how orbital speeds depend on distance from the center of our galaxy tell us that stars in the outskirts of the galaxy. True or False

stars in the outskirt orbit the galactic center

the object mean orbital speed depends only on the Earth's mass and the semi-major axis (half the longest diameter) of the object's orbit. worthy of note. the orbital speed changes depending on where in the orbit the object is. It will be greatest when closest to Earth and least when furthest from Earth.

5 0
3 years ago
Choose the correct statement of Kirchhoff's voltage law.
frutty [35]

Answer:

A) If one travels around a closed path adding the voltages for which one enters the negative reference and subtracting the voltages for which one enters the positive reference, the total is zero.

Explanation:

Kirchhoff's voltage law deals with the conservation of energy when the current flows in a closed-loop path.

It states that the algebraic sum of the voltages around any closed loop in a circuit is always zero.

In other words, the algebraic sum of all the potential differences through a loop must be equal to zero.

3 0
3 years ago
How many pounds of force must a guardrail's top rail be able to withstand?
malfutka [58]
Guardrail systems must be capable of withstanding at least 200 pounds of force applied within 2 inches of the top edge, in any direction and at any point along the edge, and without causing the top edge of the guardrail to deflect downward to a height less than 39 inches above the walking/working level.
8 0
4 years ago
Read 2 more answers
A 2,000 kg rocket is launched 12 km straight up at a constant acceleration into the sky at which point the rocket is travelling
iogann1982 [59]

Answer:

797700000 J

Explanation:

From the question,

The work done by the rocket, is given as,

W = Ek+Ep............. Equation 1

Where Ek and Ep are the potential and the kinetic energy of the rocket respectively.

Ep = mgh............ Equation 2

Ek = 1/2mv²............. equation 3

Substitute equation 2 and equation 3 into equation 1

W = mgh+1/2mv².............. Equation 4

Where m = mass of the rocket, h = height, v = velocity of the rocket, g = acceleration due to gravity.

Given: m = 2000 kg, h = 12 km = 12000 m, v = 750 m/s, g = 9.8 m/s²

Substitute into equation 4

W = 2000(12000)(9.8)+1/2(2000)(750²)

W = 235200000+562500000

W = 797700000 J

6 0
3 years ago
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