Answer: -3/2x + 3 ⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀
Answer:
Distance = 73 m
Step-by-step explanation:
Given that,
The length of a rectangle = 48 m
The width of a rectangle = 55 m
We need to find the diagonal distance. We can use the Pythagoras theorem to find it.
So, the required distance is equal to 73 m.
Least common multiple: factor them, then see what they have in common and what is leftover and multiply those expressions:
(x - 2)(x + 3) 10(x + 3)(x + 3)
Common: (x + 3)
Leftover: (x - 2), (10), (x + 3)
Common · Leftover is: (x + 3) · (x - 2) · (10) · (x + 3) = 10(x - 2)(x + 3)²
Answer: LCM is 10(x - 2)(x + 3)²
<span>Assuming the graph is y=-3(√2x)-4 and y=-3√(x-4) the transformation would be:
</span><span>The graph is compressed horizontally by a factor of 2
x=1/2x'
</span>y=-3(√2x)-4
y=-3(√x')-4 <span>
</span><span>moved left 4
x=x'-4
</span>y=-3(√x)-4
y=-3(√x'-4)-4
<span>
moved down 4
y=y'-4
</span>y=-3(√x-4)-4
y'-4=-3(√x'-4)-4
y'=-3(√x'-4)-4 +4
y'=-3(√x'-4)
Answer: C. <span>The graph is compressed horizontally by a factor of 2, moved left 4, and moved down 4.
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