Answer: 0.16
Step-by-step explanation:
Given that the run times provided are normally distributed ;
Mean(x) of distribution = 3 hours 50 minutes
Standard deviation(s) = 30 minutes
The probability that a randomly selected runner has a time less than or equal to 3 hours 20 minutes
3 hours 20 minutes = (3 hrs 50 mins - 30 mins):
This is equivalent to :
[mean(x) - 1 standard deviation]
z 1 standard deviation within the mean = 0.84
z, 1 standard deviation outside the mean equals:
P(1 - z value , 1standard deviation within the mean)
1 - 0.8413 = 0.1587
= 0.16
Speed = distance / time
30 = d / 2.5
30 * 2.5 = d
75 = d
40 = d / 1.875
40 * 1.875 = d
75 = d
50 = d / 1.5
50 * 1.5 = d
75 = d
60 = d / 1.25
60 * 1.25 = d
75 = d
24 = 75 / time
time = 75/24
time = 3.125 hours
Example of six ordered pairs with country names alongside their capitals are:
{(England, London), (USA, Washington DC), (India, New Delhi), (Nepal, Kathmandu), (Austria, Vienna), (Albania, Tirana)}.
<h3>What are Ordered Pairs?</h3>
- Ordered pair can be described as a pair of objects or numbers in a particular order.
- In an ordered pair, the order of the objects or numbers are very important. For example, (a, b) is not the same as (b, a).
Therefore, example of six ordered pairs with country names alongside their capitals are:
{(England, London), (USA, Washington DC), (India, New Delhi), (Nepal, Kathmandu), (Austria, Vienna), (Albania, Tirana)}.
Learn more about ordered pairs on:
brainly.com/question/1090891
<h3>What is the greatest common factor of 15x³y² and 20x⁴y⁴? </h3>
<em>First we have to find the factors of 15x³y²</em>
<em>15x³y² = 3 * 5x³y² </em>
<em>Then we have to find the factors of 20x⁴y⁴</em>
<em>20x⁴y⁴ = 2²x¹y² * 5x³y²</em>
<em>Now we have to find the common factors to both numbers.</em>
<em>The common factors are </em><em>5x³y²</em>
Answer : GCF = (15x³y²,20x⁴y⁴) = 5x³y²
Hope this helps!
