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Ronch [10]
3 years ago
13

Why are low sulfur fuels an advantage to the environment

Chemistry
1 answer:
ipn [44]3 years ago
3 0

Answer: Low sulphur fuels reduce tailpipe CO, HC, and NOx emissions from catalyst-equipped gasoline vehicles

Explanation:

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A jet airplane reaches 750 km/h on a certain flight. What distance does it cover in <br> 10 min?
malfutka [58]

The distance that jet covered in 10 min is 125 Km

calculation

distance = speed  x time

speed=750 km/h

time= 10/60hrs

=750 x10/60=125 Km

3 0
3 years ago
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Which explanations did you include in your response? Check all that apply. The oxidation number of carbon changes from -1 to +4.
Kaylis [27]

Answer:

B, E

Explanation:

Edge

5 0
2 years ago
What is the enthalpy of combustion (per mole) of C4H10 (g)? 
Artemon [7]
The balanced chemical reaction for the complete combustion of C4H10 is shown below:

                    C4H10 + (3/2)O2 --> 4CO2 + 5H2O

The enthalpy of formation are listed below:
          C4H10: -2876.9 kJ/mol
              O2:   none (because it is pure substance)
             CO2: -393.5 kJ/mol
             H2O: -285.8 kJ/mol

The enthalpy of combustion is computed by subtracting the total enthalpy formation of the reactants from that of the products.

               ΔHc = (4)(-393.5 kJ/mol) + (5)(-285.8 kJ/mol) - (-2876.9 kJ/mol)
                       = -<em>126.1 kJ</em>

Thus, the enthalpy of combustion of the carbon is -126.1 kJ. 
5 0
3 years ago
Read 2 more answers
How did the construction of a parking lot, hiking trail, and playground affect the fish populations in the pond? PLEASE HELP.
Tpy6a [65]
A),b),c),d) answers?
4 0
3 years ago
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The density of water is 1.00 g/ml at 4°c. how many water molecules are present in 2.36 ml of water at this temperature?
spin [16.1K]

Mass of 1 ml of water 1 g as density of water 1.00 g/ml at 4° C. So, mass of 2.36 ml of water \frac{1}{2.36} g= 0.423 g.

Molecular mass of water is 18 g which indicates 18 g water contains 6.023 X 10^{23} number of water molecules. So, 0.423 g of water contains \frac{6.023 X 10^{23} X 0.423 }{18}  g = 0.141 X 10^{23} number of water molecules= 1.41 X 10^{22} number of water molecules.

5 0
3 years ago
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