All categories

3 years ago

How many grams are in 2.40 moles of sodium hydroxide (NaOH)?

Chemistry

1 answer:

Bogdan [553]3 years ago

5 0

Answer:

96g

Explanation:

Given parameters:

Number of moles of NaOH = 2.4moles

Unknown:

Mass of NaOH = ?

Solution:

The mass of a substance given the number of moles can be found using the expression below;

Mass of NaOH = Number of moles x molar mass;

Molar mass of NaOH = 23 + 16 + 1 = 40g/mol

Now input the parameters and solve;

Mass of NaOH = 2.4 x 40 = 96g

You might be interested in

5. Calculate the mass percent of carbon in C3H8

Anuta_ua [19.1K]

Answer: How to calculate the mass percent by using these instructions

1.The molar mass is the mass of a given chemical element or chemical compound (g) divided by the amount of substance (mol).

2.The molar mass of a compound can be calculated by adding the standard atomic masses (in g/mol) of the constituent atoms.

Explanation:

7 0

3 years ago

PLEASE HELP ME classify this reaction

Mumz [18]

Answer:

2. combustion is anything reaction undergoing heat energy for it's .......

5 0

3 years ago

A 25.0 mL sample of a solution of an unknown compound is titrated with a 0.115 M NaOH solution. The titration curve above was ob

Mnenie [13.5K]

Answer:

Weak acid

Explanation:

A titration curve is a graphical description of the change in pH of the solution in the conical flask as the reagent is added from the burette. A titration curve can be plotted for the different kinds of acid and base titrations. The volume of the titrant is always plotted as the independent variable and the pH of the solution as the dependent variable. The equivalence point is read off from the titration curve. A titration curve is very important because it shows the pH at various points during the titration.

A weak acid/strong base titration leads to an equivalence point above 7. From the question, we were told that the pH at equivalence point lies around 8. Hence the unknown substance must be a weak acid.

3 0

4 years ago

Help me I hate science so much

mestny [16]

Answer:

it would be sciemce

Explanation:

yeah because its hargf

8 0

3 years ago

Read 2 more answers

For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ

Komok [63]

Answer:

Check the explanation

Explanation:

Answer – Given, $H_3PO_4$ acid and there are three Ka values

$K_{a1}=6.9x10^8, K_{a2} = 6.2X10^8, and K_{a3}=4.8X10^{13}$

The transformation of $H_2PO_4- (aq) to HPO_4^2-(aq)$ is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

Mass of KH2PO4 = 22.0 g , mass of Na2HPO4 = 32.0 g , volume = 1.00 L

First we need to calculate moles of each

Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

= 0.162 moles

Moles of Na2HPO4 = 32.0 g /141.96 g.mol-1

= 0.225 moles

[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

pKa2 = -log Ka

= -log 6.2x10-8

= 7.21

We know Henderson-Hasselbalch equation

pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

= 7.35

The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

6 0

3 years ago