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Paladinen [302]
3 years ago
12

How many grams are in 2.40 moles of sodium hydroxide (NaOH)?

Chemistry
1 answer:
Bogdan [553]3 years ago
5 0

Answer:

96g

Explanation:

Given parameters:

Number of moles of NaOH = 2.4moles

Unknown:

Mass of NaOH = ?

Solution:

The mass of a substance given the number of moles can be found using the expression below;

     Mass of NaOH  = Number of moles x molar mass;

  Molar mass of NaOH  = 23 + 16 + 1 = 40g/mol

Now input the parameters and solve;

    Mass of NaOH  = 2.4 x 40  = 96g

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Fruit juice when boiled taste sweeter than sucrose because ​
irina1246 [14]

Answer :see explanation

Explanation:

the sweet carbohydrate in fruit is not sucrose , it is fructose.

and fructose tastes sweeter than sucrose

fructose and glucose minus water equals sucrose

and fructose is sweeter than glucose

6 0
2 years ago
How many milliliters of a 3.4 M NaCl solution would be needed to prepare each solution?
Ksenya-84 [330]

Answer:

a. Approximately 1.3\; \rm mL.

b. Approximately 7.2\; \rm mL.

Explanation:

The unit of concentration "\rm M" is equivalent to "\rm mol \cdot L^{-1}", which means "moles per liter."

However, the volume of both solutions were given in mililiters \rm mL. Convert these volumes to liters:

\displaystyle 45\; \rm mL = 45\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.045\; \rm L.

\displaystyle 330\; \rm mL = 330\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.330\; \rm L.

In a solution of volume V where the concentration of a solute is c, there would be c \cdot V (moles of) formula units of this solute.

Calculate the number of moles of \rm NaCl formula units in each of the two solutions:

Solution in a.:

n = c \cdot V = 0.045\; \rm L \times 0.10\; \rm mol \cdot L^{-1} = 0.0045\; \rm mol.

Solution in b.:

n = c \cdot V = 0.330\; \rm L \times 0.074\; \rm mol \cdot L^{-1} = 0.02442\; \rm mol.

What volume of that 3.4\; \rm M (same as 3.4 \; \rm mol \cdot L^{-1}) \rm NaCl solution would contain that many

For the solution in a.:

\displaystyle V = \frac{n}{c} = \frac{0.0045\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0013\; \rm L.

Convert the unit of that volume to milliliters:

\displaystyle 0.0013\; \rm L = 0.0013\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 1.3\; \rm mL.

Similarly, for the solution in b.:

\displaystyle V = \frac{n}{c} = \frac{0.02442\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0072\; \rm L.

Convert the unit of that volume to milliliters:

\displaystyle 0.0072\; \rm L = 0.0072\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 7.2\; \rm mL.

8 0
3 years ago
What is the percent by mass of water in Na2SO4 • 10H2O?
bulgar [2K]
We determine the percent by mass of water in the compound by dividing the mass of  water by the total mass. The total mass of Na2SO4.10H2O is equal to 322 g. The mass of water is 180 g. 
       
                    percent by mass of water = (180 / 322)*(100 %) = 55.9%
5 0
4 years ago
Read 2 more answers
Which substance has the highest viscosity?
Lemur [1.5K]
Room temperature has the highest viscosity
6 0
3 years ago
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When a metal reacts with oxygen gas what is the product formed
beks73 [17]

Answer:

Hello There!!

Explanation:

When a metal reacts with oxygen gas metal oxide forms.Whenever a compound or element reacts with oxygen It turns to oxide.

hope this helps,have a great day!!

~Pinky~

6 0
3 years ago
Read 2 more answers
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