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harkovskaia [24]
3 years ago
11

Which statement compares the masses of two subatomic particles

Chemistry
1 answer:
Lelechka [254]3 years ago
4 0
I don't see any options to choose from, but, I have seen this question.

When comparing the masses of two subatomic particles, the mass of a proton is greater than the mass of an electron.


Brainlest answer is always appreciated ( ͡ ͜ʖ ͡ )
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Why is air considered a mixture not a compound?
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8 0
3 years ago
Which best explains why water is able to “stick” to the side of glass?
AveGali [126]

Explanation:

Adhesion means the ability to stick on the surface of another substance.

Water exhibits adhesive forces due to which it is able to stick to the glass.  Due to adhesive forces water spreads over the surface of glass and sticks to it.

These adhesive forces between the glass and water enough that it deforms the spherical shape of water molecules and help them stick to the surface of glass. As a result, adhesive forces overcome the repulsion between like molecules.

Hence, water is able to “stick” to the side of glass due to strong adhesive forces.


4 0
3 years ago
Read 2 more answers
How many moles of helium atoms are there in
fredd [130]

a is the correct answer .

2.4 × 10^24

6 0
3 years ago
A 5.00g of X, the product of organic synthesis is obtained in a 1.0 dm3 aqueous solution. Calculate the mass of X that can be ex
Anestetic [448]

Answer:

mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

Explanation:

The partition coefficient of X between ethoxy ethane (ether) and water, K is given by the formula

K = concentration of X in ether/concentration of X in water

Partition coefficient, K(X) between ethoxy ethane and water = 40

Concentration of X in ether = mass(g)/volume(dm³)

Mass of X in ether = m g

Volume of ether = 50/1000 dm³ = 0.05 dm³

Concentration of X in ether = (m/0.05) g/dm³

Concentration of X in water = mass(g)/volume(dm³)

Mass of X in water left after extraction with ether = (5 - m) g

Volume of water = 1 dm³

Concentration of X in water = (5 - m/1) g/dm³

Using K = concentration of X in ether/concentration of X in water;

40 = (m/0.05)/(5 - m)

(m/0.05) = 40 × (5 - m)

(m/0.05) = 200 - 40m

m = 0.05 × (200 - 40m)

m = 10 - 2m

3m = 10

m = 10/3

m = 3.33 g of X

Therefore, mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

8 0
3 years ago
I am a celestial body that does not produce light. I orbit a planet
Artyom0805 [142]
A moon would be the correct answer.
5 0
3 years ago
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