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3 years ago

The blue dot is at what value on the number line ?

Mathematics

2 answers:

Veronika [31]3 years ago

8 0

Answer:

Step-by-step explanation:

nalin [4]3 years ago

7 0

Answer:

0, start at -6 and count up(down) by 2 from every dot

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I am so lost in geometry. Help?

icang [17]

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29. (4,3) I look at the distance between the x coordinates and add it to the end that is the middle and do the same for the y.

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Hope this helped. Let me know if you need any more help!

3 0

3 years ago

Can someone plz help me with this!!!

zalisa [80]

Answer:

100

Step-by-step explanation:

an isosceles triangle is equal so if one side is 100 degrees, the other side is too

8 0

3 years ago

Read 2 more answers

How do you convert 20/12 to a proper fraction

julia-pushkina [17]

Answer:

Step-by-step explanation:

4 0

3 years ago

On the same grid draw, draw the graph of y= x - 1

Gala2k [10]

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3 years ago

estimate the number of first-year students at an assembly meeting. He surveys 60 students and finds that 24 of them are first-ye

bogdanovich [222]

Answer:

The values needed to calculate a confidence interval at the 95% confidence level are $z = 1.96, n = 60, \pi = \frac{24}{60} = 0.4$

The 95% confidence interval for the proportion of first-year students at an assembly meeting is (0.276, 0.524).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 60, \pi = \frac{24}{60} = 0.4$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The values needed to calculate a confidence interval at the 95% confidence level are $z = 1.96, n = 60, \pi = \frac{24}{60} = 0.4$

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 1.96\sqrt{\frac{0.4*0.6}{60}} = 0.276$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 1.96\sqrt{\frac{0.4*0.6}{60}} = 0.524$

The 95% confidence interval for the proportion of first-year students at an assembly meeting is (0.276, 0.524).

6 0

3 years ago