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sp2606 [1]
2 years ago
13

Can someone please help me with this? It's the only question I need help with (since we are reviewing things that we learned in

6th grade again)

Mathematics
2 answers:
BartSMP [9]2 years ago
8 0

Answer: 18 mega rolls

Step-by-step explanation:                      

Dovator [93]2 years ago
8 0

Answer:

the second one is a better deal.

Step-by-step explanation:

<em>first deal:</em>

6 rolls for 9.24

9.24/6 = 1.54

1.54$ per roll

<em>second deal:</em>

18 rolls for 27.54

27.54/18 = 1.53

1.53$ per roll

the second one is one cent cheaper

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How do you solve 5-4x&lt;95
mario62 [17]

5 - 4x < 95 \\  - 4x  < 95 - 5 \\  - 4x = 90 \\ x =  -  \frac{90}{4}  \\  \boxed{ x =  -  \frac{45}{2} }

8 0
2 years ago
What is the area of the region shown on the map?
Advocard [28]
The area of the region on the map is 97.5 miles
8 0
2 years ago
Read 2 more answers
Points J and K lie in plane H.
Vlad [161]

Answer: 1

Step-by-step explanation:

From the given picture, it can be seen that there is a plane H on which two pints J and K are located.

One of the Axiom in Euclid's geometry says that <em>"Through any given two points X and Y, only one and only one  line can be drawn "</em>

Therefore by Axiom in Euclid's geometry , for the given points J and K in plane H , only one line can be drawn  through points J and K.

6 0
3 years ago
Read 2 more answers
PQRS is parallelogram,QM is the height of Q to SR and ON is the height from Q to PS.It SR =12 cm and QM =7.6 cm find the area of
Oksanka [162]

Given: SR=12cm, QM=7.6cm, PS=8cm.

Area of parallelogram=base×height

=12×7.6=91.2cm2.

Area of parallelogram=base×height

⇒91.2=8×QN

⇒QN=891.2=11.4cm.

5 0
2 years ago
Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are
Kruka [31]

Answer:

Step-by-step explanation:

The formula for determining the confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

Where

x1 = sample mean of type A paint

x2 = sample mean of type B paint

s1 = sample standard deviation type A paint

s2 = sample standard for type B paint

n1 = number of samples of type A paint

n2 = number of samples of type B paint

From the information given,

x1 = 75.7

s1 = 4.5

n1 = 11

x2 = 64.3

s2 = 5.1

n2 = 9

x1 - x2 = 75.7 - 64.3 = 11.4

√(s1²/n1 + s2²/n2) = √(4.5²/11 + 5.1²/9) = √4.709

Degree of freedom = (n1 - 1) + (n2 - 1)

df = (11 - 1) + (9 - 1) = 18

For the 98% confidence interval, the z score from the t distribution table is 2.552

Margin of error = 2.552√4.709 = 5.55

The upper boundary for the confidence interval is

11.4 + 5.55 = 16.95 hours

The lower boundary for the confidence interval is

11.4 - 5.55 = 5.85 hours

The correct option is

B. 5.85 hrs < μ1 - μ2 < 16.95 hrs

4 0
2 years ago
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