A line is parallel to y= 1/2x +6 and passes through (–8, 0). What is the equation of the line?
2 answers:
Answer:
y = 1/2x + 4
Step-by-step explanation:
y = 1/2x + b
0 = -4 + b
b = 4
y = 1/2x + 4
keeping in mind that parallel lines have exactly the same slope, hmmm so what's the slope of the equation above?

so, we're really looking for the equation of a line whose slope is 1/2 and runs through (-8 , 0)
![\bf (\stackrel{x_1}{-8}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{\cfrac{1}{2}}[x-\stackrel{x_1}{(-8)}] \\\\\\ y=\cfrac{1}{2}(x+8)\implies y=\cfrac{1}{2}x+4](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B-8%7D~%2C~%5Cstackrel%7By_1%7D%7B0%7D%29~%5Chspace%7B10em%7D%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B2%7D%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-%5Cstackrel%7By_1%7D%7B0%7D%3D%5Cstackrel%7Bm%7D%7B%5Ccfrac%7B1%7D%7B2%7D%7D%5Bx-%5Cstackrel%7Bx_1%7D%7B%28-8%29%7D%5D%20%5C%5C%5C%5C%5C%5C%20y%3D%5Ccfrac%7B1%7D%7B2%7D%28x%2B8%29%5Cimplies%20y%3D%5Ccfrac%7B1%7D%7B2%7Dx%2B4)
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