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sdas [7]
3 years ago
10

Write and solve a proportion to answer the question. 72 is what percent of 45?

Mathematics
1 answer:
Ivanshal [37]3 years ago
8 0

Answer:

160% is for 72 of 45

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Kkkkkkkkkk HELPPPP RNNNNNNNN
k0ka [10]

Answer:

c

Step-by-step explanation:

every vertical line must doesn't have any accident with graph like the graph C.

7 0
3 years ago
Here is the next one:)
butalik [34]

Answer:

O Sin (53) = 21/29

O Sin (37) = 20/29

Step-by-step explanation:

In a triangle, the sine is opposite over hypotenuse, the cosine is adjacent over hypotenuse, and the tangent is opposite over adjacent.

8 0
3 years ago
Read 2 more answers
A car travels 15 miles per gallon of
Arlecino [84]

Answer:

15x = y

Step-by-step explanation:

15 times the gallons of gas =  miles

15x = y

5 0
3 years ago
Need help figuring this equation 1/12c =.6
soldi70 [24.7K]
1/12c = 0.6

To remove a fraction you simply multiply it by its inverse fraction (take the original fraction and flip it! So, multiply it by 12/1 (which is the same as saying 12).

12(1/12c) = 0.6*12

The 12 cancels out leaving this: 

c  = 0.6 * 12
c = 7.2

If you don't have or are allowed to use a calculator. To compute that you simply make 0.6 into a fraction then multiply the numerator by 12. .6 is in the tenths place so you can write it like this: 
6/10 simplifying it becomes, 3/5

3/5 * 12 = 36/5

Now! That was assuming 1/12c was written like this: 
(1/12)c = 0.6

If it was actually written like this: 
1/(12c) = 0.6 then you'll do this. 

Multiply 0.6 by 12c. Which will get you 7.2c. After that you need to get c alone, so you divide both sides by 7.2. Yielding the result: 

1/7.2 = c 

c = 0.1389...


5 0
3 years ago
The z-score associated with 95% is 1.96. If the sample mean is 200 and the standard deviation is 30, find the upper limit of the
ziro4ka [17]

Answer:

The upper limit of the 95% confidence interval is:

C.I_u = 200 + (58.8/\sqrt{n})

Step-by-step explanation:

The formula is given as:

C.I = μ ± Z*σ/\sqrt{n}

The upper limit => C.I_u = μ + Z*σ/\sqrt{n}

The lower limit => C.I_l = μ - Z*σ/\sqrt{n}

The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.

The upper limit => C.I_u = 200 + 1.96*(30/\sqrt{n})

                                    = 200 + (1.96*30)/\sqrt{n}

                                    = 200 + 58.8/\sqrt{n}

5 0
3 years ago
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