Answer:
<u>Heating water with an open flame</u>
<u>Explanation:</u>
Remember, we are told in the label that Acetone is a "flammable liquid and vapor." <em>Being flammable means the substance can easily be set on fire</em>, and we would expect an open flame from heating water to trigger an explosion (a disaster) in which the Acetone is set on fire causing life-threatening dangers to the second group of students.
Answer:
Because of statements (a), (c) and (d).
Explanation:
Let's evaluate each statement to know why they focus on higher alcohols instead of ethanol:
(a) It is easier to produce higher alcohols in microbes than it is to produce ethanol<u>.</u> This is true<u> since ethanol is the major biofuel in the world because it can be easily produced by fermentation technology developed a long time ago. Recently, higher alcohols are produced from microorganisms that are used as microbial cell factories.</u>
(b) Higher alcohols have a higher hygroscopicity than ethanol. This is false since ethanol is more hygroscopic than higher alcohols.
(c) Higher alcohols have a lower vapor pressure than ethanol. This is true, ethanol has a higher vapor pressure than higher alcohols. The vapor pressure is important since it can affect the proper cold starting of the engine.
(d) Higher alcohols have a higher energy density than ethanol. This is true since the production of higher alcohols as biofuels is more desirable than the ethanol because higher alcohols have a high energy density and other more advantages than the use of ethanol.
Therefore the answer of why did they focus on higher alcohols to add to or substitute gasoline instead of ethanol is because of the statements (a), (c) and (d).
I hope it helps you!
Answer:
Explanation:
Hello.
In this case, we can see that the mass of carbon of the unknown compound comes from the yielded mass of carbon dioxide, thus, we compute the moles of carbon as follows:
Moreover, the mass of hydrogen comes from the yielded water, therefore we can also compute the moles of water:
Then, to find the subscripts in the empirical formula, we divide by the moles of carbon as the smallest:
Whose molar mass is:
Thus, the ratio of the molecular formula to the empirical formula is:
Therefore, the molecular formula is twice the empirical formula:
Which is actually ethane.
Regards.
the correct answer is option ( A ) Amine
Hope it helps you
have a nice day dear
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