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LuckyWell [14K]
3 years ago
10

When you rub two sticks together, it causes friction. What does the friction produce? A. sound energy B. heat energy C. electric

al energy D. light energy
Physics
1 answer:
Temka [501]3 years ago
6 0

Answer:

B

Explanation:

When rubbing two sticks together it causes friction witch at fast enough friction rate produces heat energy

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1. A ray of light traveling from air into crown glass strikes the surface at an angle of 30 degrees. What will the
Readme [11.4K]

Answer: acute

Explanation:

4 0
4 years ago
A car accelerates to the right from 12 m/s to 30 m/s in 6.0 s. What was its acceleration and displacement during this time inter
Scorpion4ik [409]

Answer:

Acceleration = 3m/s^2

Displacement = 126 m

Explanation:

The velocity changed from 12 to 30 m/s in 6 seconds. Using the formula for acceleration we get

(30-12)/6= 18/6= 3m/s^2

Displacement is d=.5a*t^2+v0*t

Inputting acceleration, time, and velocity leaves us with

d=1.5 * 36 + 12 * 6 = 54 + 72 = 126 m

7 0
4 years ago
The coefficient of kinetic friction between a suitcase and the floor is 2.76. if the suitcase has a mass of 71.5 kg, how far can
mihalych1998 [28]

suitcase can be pushed to a distance of 0.35 m

Explanation:

Work done= Ff d

w= 670 J

Ff= force of friction

d= distance

force of friction is given by Ff=μ mg

μ= coefficient of friction=2.76

m=mass=71.5 kg

so Ff= (2.76) (71.5) (9.8)

Ff=1934 N

so W= Ff d

670= 1934 d

d=0.35 m

8 0
3 years ago
A driver notices that her 1280 kg car slows down from 92 km/h to 68 km/h in about 7.5 s on the level when it is in neutral. Appr
sweet-ann [11.9K]

Answer:

P = 25299.75 watts

Since 80km/h is the average speed of 92km/h and 68km/h, the power (in watts) is needed to keep the car traveling at a constant 80 km/h is P = 25299.75 watts

Explanation:

Given;

Mass of car m = 1280kg

initial speed v1 = 92km/h = 92×1000/3600 m/s= 25.56m/s

Final speed v2 = 68km/h = 68×1000/3600 m/s= 18.89m/s

time taken t = 7.5s

Change in the kinetic energy of the car within that period;

∆K.E = 1/2 ×mv1^2 - 1/2 × mv2^2

∆K.E = 0.5m(v1^2 -v2^2)

Substituting the values, we have;

∆K.E = 0.5×1280(25.56^2 - 18.89^2)

∆K.E = 189748.16J

Power used during this Change;

Power P = ∆K.E/t

Substituting the values;

P = 189748.16/7.5

P = 25299.75 watts

Since 80km/h is the average speed of 92km/h and 68km/h, the power (in watts) is needed to keep the car traveling at a constant 80 km/h is P = 25299.75 watts

7 0
3 years ago
A helicopter flying at a distance of 20.0 km from a radio transmitter receives a signal of intensity 35.1 μW/m2.
irinina [24]

Answer:

a) 0.162 V/m

b) 0.54 nT

c) 22 kW

Explanation:

Given

Distance of flight, d = 20 km

Intensity of signal, I = 35.1 μW/m²

Magnitude of the electric component is gotten using the formula

E(m) = √(2Iμc), where

E(m) = √(2 * 35*10^-6 * 4*3.142*10^-7 * 3*10^8)

E(m) = √(2 * 35*10^-6 * 1.257*10^-6 * 3*10^8)

E(m) = √0.0264

E(m) = 0.162 V/m

Magnitude of magnetic component can be gotten by using the relation

B(m) = E(m) / c

B(m) = 0.162 / 3*10^8

B(m) = 5.4*10^-10

B(m) = 0.54 nT

Transmission power, P = IA

where A = 1/2 * 4πr²

P = 2Iπr²

P = 2 * 35*10^-6 * 3.142 * (10000)²

P = 2 * 35*10^-6 * 3.142 * 1*10^8

P = 21994 W

Thus, the transmission power is 22 kW

5 0
3 years ago
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