A thought experiment aims to promote speculative thinking, logical reasoning, and paradigm shifts. Thought experiments force us to address problems we find difficult to answer, which forces us out of our comfort zone. They highlight knowledge gaps and aid in recognizing the boundaries of what is knowable.
<h3>What are thought experiments?</h3>
Thought experiments are imaginative methods for examining the nature of things. They are employed for a variety of purposes in a number of disciplines, including physics, economics, history, mathematics, and philosophy.
A thought experiment is a test that we do in our minds. Here, we will imagine a specific scenario, consider some of its repercussions, and come to a broad conclusion.
Therefore, a thought experiment aims to promote speculative thinking, logical reasoning, and paradigm shifts. Thought experiments force us to address problems we find difficult to answer, which forces us out of our comfort zone. They highlight knowledge gaps and aid in recognizing the boundaries of what is knowable.
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To calculate and solve the problem it is necessary to apply the concepts related to resistance and resistivity.
The equation that is responsible for relating the two variables is:
Where,
R= Resistance of the conductor
Resistivity of the conductor material
L = Length
A = Cross-sectional area of conductor
With the previous values the area of the muscle (Real Muscle-82%)is,
Using the equation from Resistance we have that at the muscle the value is:
At the same time we can make the same process to calculate the resistance of the fat, then
The resistance of the fat would be,
Then the total resistance in a set as the previously writen, i.e, in parallel is:
We can here apply Ohm's law, then
It's moving, in a straight line and at a constant speed. It can't be accelerating.
First, we need to find the number of protons, which is the total mass divided by the mass of one proton:
protons
Then, the total charge is the number of protons times the charge of a single proton:
Answer:
materials: solid dissolved in a liquid
independent variable: temperature
Explanation:
I got it right