Answer:
The two scenarios differ.
P(Scenario A) = 0.107
P(Scenario B) = 0.265
Step-by-step explanation:
The two scenarios are different because for the second one you are alredy assuming that the first 3 cards are not hearths, and for that reason, B is more likely to happen that A.
For B to happen, you need to notice that since you remove 3 cards from your deck that are not hearts, then your deck has only 49 cards, and 13 of them are hearts. The probability for a heart to show up is, as a result 13/49 = 0.265 because you have 13 favourable cases from 49 possible.
For A, you need the first card to be anything but a heart. Since 13 cards of the deck are herts, 39 are not, and the probability of that hapening is 39/52 = 3/4. After you remove your first card, the probability of the second one not being heart is 38/51, and the probability for the third one is 37/50 (you are removing one favourable case and one case for the total of cases each time). The probability for the fourth card being a heart assuming that the first three are not was calculated before and it gives us a result of 13/49.
Multiplying everything, we obtain that
P(A) = 3/4*38/51*37/50*13/49 = 0.107.
Answer:
Blanks top to bottom: 6^2, 36, 9, 108, 101
Step-by-step explanation:
Use PEMDAS which stands for parentheses, exponents, multiplication, division, addition, and subtraction. Listed in this specific order, you must look and solve for each one first, starting with parentheses.
4.
12 × ((4+2)^2/4) - 7
Solve for inside of parentheses first:
12 × ((6)^2/4) - 7
12 × (36/4) - 7
12 × 9 - 7
108 - 7
101
The answer is c because that’s how much is 2 liters
Answer:
(?) = (x-5)
Step-by-step explanation:
Use difference of squares:
I’m pretty sure the answer is 30... right? Because you’d multiply 10 and 3
