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larisa [96]
3 years ago
13

Based on a poll of 1000 residents, a newspaper article claims that 62% of the residents in town favor the development of a recre

ational
park on the west side of town. A community action group interested in preserving the environment claims that 45% of the town's
residents favor the development of a recreational park.
To determine whether the sample supports the
population proportion, a simulation of 100 trials is run, each with a
sample of 200, using the point estimate of the population. The minimum sample proportion from the simulation is 0.46 and the
maximum sample proportion is 0.76.
What is the point estimate of the population?
The margin of error of the population proportion is found using an estimate of the standard deviation. What is the
interval estimate of the true population proportion?
The margin of error of the population proportion is found using the half the range.
What is the interval estimate of the true population proportion?
Is the community action group's claim likely based on either interval estimate of the true population proportion?
Explain.
Mathematics
1 answer:
nlexa [21]3 years ago
6 0
Estimate of population 0.61
(b) Margin of error = 0.07 The real population interval estimation is ± 7%.
c). Margin of error = 0.15
d) The real population's interval estimation is ± 15%
e). Yes, the action argument of the group is based on a half-range estimation of the true population. The reason that 62% ± 15% = 47%, or 77%, while 47% is similar to 45%, as the Collective action group states. Hope this helps! Mark Brainly please!
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e follSOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the general equation of an ellipse

\frac{\mleft(x-h\mright)^2}{a^2}+\frac{(y-h)^2}{b^2^{}}=1

STEP 2: Identify the parameters

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\begin{gathered} 2a=24,a=\frac{24}{2}=12 \\ 2b=20,b=\frac{20}{2}=10 \end{gathered}

STEP 3: Get the equation of the ellipse

\begin{gathered} By\text{ substitution,} \\ \frac{(x-h)^2}{a^2}+\frac{(y-h)^2}{b^2}=1 \\ \frac{(x-0)^2}{12^2}+\frac{(y-0)^2}{10^2}=1=\frac{x^2}{144}+\frac{y^2}{100}=1 \end{gathered}

STEP 4: Pick the nearest equation from the options,

Hence, the equation of the ellipse in the image is given as:

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OPTION A

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