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Natalija [7]
3 years ago
7

Assume a future where security counter measures against DoS attacks are much more widely implemented than at present. In this fu

ture network, anti-spoofing and directed broadcast filters are widely deployed. Also, the security of PCs and workstations is much greater, making the creation of botnets difficult. Do the administrators of server systems still have to be concerned about, and take further countermeasures against, DoS attacks? If so, what types of attacks can still occur, and what measures can be taken to reduce their impact? Explain in detail with valid diagram and example.
Computers and Technology
1 answer:
Amiraneli [1.4K]3 years ago
7 0

Answer:

yes administrators have to be concerned

Explanation:

It is necessary for countermeasures to be taken against DoS attacks

The types of attacks that can still occur are:

If the network connection get to be overloaded,  there could be flash crown of this computer system and fraudulent activities maybe initiated. By flash crowd  we mean that the there is a great deal of traffic on the system and this could cause the network connection to be destroyed.

To reduce the impact of this kind of attacks,

1. there should be enough or excess network bandwidth  and distributed servers should be replicated if there is a possibility that network could get to be overloaded.

2. restriction is more commonly done on sporting sites. Restriction brings about an increase in implementation cost.

3. The impact of this type of attack can be reduced by stopping unwanted traffic throught the implementation of filters

4. Use strong antivirus on computer sytems that are used to connect to the internet

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Answer:

In Python

def getpointValue(subject):

   if subject >= 75:        point = 4; grade = 'A'

   elif subject >= 60:        point = 3; grade ='B'

   elif point >= 50:        point = 2; grade = 'C'

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mkt = int(input(subjects[1]+": "))

eco = int(input(subjects[2]+": "))

mis = int(input(subjects[3]+": "))

acctgrade = getpointValue(acct)

print(subjects[0]+" Grade: "+str(acctgrade[1]))

mktgrade = getpointValue(mkt)

print(subjects[1]+" Grade: "+str(mktgrade[1]))

ecograde = getpointValue(eco)

print(subjects[2]+" Grade: "+str(ecograde[1]))

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totalpoint = (acctgrade[0] + mktgrade[0] + ecograde[0] + misgrade[0]) * 3

gpa = totalpoint/12

print("GPA: "+str(gpa))

Explanation:

<em>The solution I provided uses a function to return the letter grade and the point of each subject</em>

<em>I've added the explanation as an attachment where I used comment to explain difficult lines</em>

<em />

Download txt
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