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3 years ago

Please HELP QUICKLY WHICH ONE IS CORRECT

Mathematics

2 answers:

enot [183]3 years ago

8 0

Answer:

24 ounce package ( cheapest )

GuDViN [60]3 years ago

5 0

Answer: 24 ounces

Step-by-step explanation:

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Abby has 16 grapes Jason has 9 grapes how many more grapes does Abby have than Jason

Novay_Z [31]

Abby has 7 more grapes because 16-9=7

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3 years ago

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Help with this question please! Give explanation! Big points

BigorU [14]

Answer:

$y = 2$

Step-by-step explanation:

This answer is easily found using the Pythagorean Theorem:

${a}^{2} + {b}^{2} = {c}^{2}$

where A and B are the legs, and C is the hypotenuse of the triangle.

${(16)}^{2} + {(6y)}^{2} = {(10y)}^{2} \\ 256 + 36{y}^{2} = 100 {y}^{2} \\ 256 = 64 {y}^{2} \\ \sqrt{256} = \sqrt{64 {y}^{2}} \\ 16 = 8y \\ y = 2$

5 0

3 years ago

Please help me somebody! <3

Misha Larkins [42]

I believe it would be -17m-4/8

8 0

3 years ago

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I can't solve it, so, here goes nothin'. "Some people are on a train, 19 people get off at one stop, then, the next one 13. Now

Stolb23 [73]

19+13=32

32+63=95

95-4=91

91+10=101

This means that 101 people are now on the bus.

HOPE THIS HELPS <3

4 0

2 years ago

At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is

Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = $\frac{dx}{dt}$

ship B is sailing north at 20 km/h = $\frac{dy}{dt}$

here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find $\frac{dz}{dt}$ at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

$z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we | | get \\$

$z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h$

derivative first equation w . r. to t we get

$2z\frac{dz}{dt} =$ $-2(130-x)\frac{dx}{dt}$ $+2y\frac{dy}{dt}$

$\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]$

$\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }$

$= \frac{1100}{85.44}\\ = 12.87km/h$

8 0

3 years ago