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Deffense [45]
3 years ago
11

Please HELP QUICKLY WHICH ONE IS CORRECT

Mathematics
2 answers:
enot [183]3 years ago
8 0

Answer:

24 ounce package ( cheapest )

GuDViN [60]3 years ago
5 0

Answer: 24 ounces

Step-by-step explanation:

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Jenny earned 92 of a possible 120 points on a test. She lost 4 points for each
Kryger [21]
Jenny missed 7 problems on the 120 point test
7 0
3 years ago
Read 2 more answers
Ok im super confused bc like it ask me put i dont know what to put.............pls help me
Ilya [14]

Answer:

u drag the green dot thing over to the coordinate (6,8)

Step-by-step explanation:

i put a black dot where i think ur supposed to drag the green dot to

3 0
2 years ago
A triangle has two side lenths of 1 and 16 what is the largest possible whole-number length of the third side?
Afina-wow [57]

Answer:

16

Step-by-step explanation:

Given that:

Length of two sides of the triangle = 1 and 16 ;

The largest possible whole-number length of the third side would be ;

Recall from triangle inequality theorem; the length of any two sides of a triangle is greater than the third side. Therefore. The largest possible whole number value the third side could have is:

Assume the third side is the largest :

Then, the third side must be less than the sum of the other two sides ;

Third side < (16 + 1)

Third side < 17

Therefore, the closest whole number lesser than the sum of the other two sides is (17 - 1) = 16

6 0
3 years ago
Use tables to show which of these ratios are equivalent: 4/6, 10/25, and 6/15
hoa [83]

Answer:

4/6 and 6/15

Step-by-step explanation:

simplify all fractions to lowest possible.

4/6 = 2/3

10/25 = 2/5

6/15 = 2/3

4/6 and 6/15 are equivalent

8 0
3 years ago
The sum of a two digit number and the number obtained by interchanging the digits is 132. If the two digits differ by 2, find th
damaskus [11]

Answer:

A two-digit number can be written as:

a*10 + b*1

Where a and b are single-digit numbers, and a ≠ 0.

We know that:

"The sum of a two-digit number and the number obtained by interchanging the digits is 132."

then:

a*10 + b*1 + (b*10 + a*1) = 132

And we also know that the digits differ by 2.

then:

a = b + 2

or

a =  b - 2

So let's solve this:

We start with the equation:

a*10 + b*1 + (b*10 + a*1) = 132

(a*10 + a) + (b*10 + b) = 132

a*11 + b*11 = 132

(a + b)*11 = 132

(a + b) = 132/11 = 12

Then:

a + b = 12

And remember that:

a = b + 2

or

a = b - 2

Then if we select the first one, we get:

a + b = 12

(b + 2) + b = 12

2*b + 2 = 12

2*b = 12 -2 = 10

b = 10/2 = 5

b = 5

then a = b + 2= 5 + 2 = 7

The number is 75.

And if we selected:

a = b - 2, we would get the number 57.

Both are valid solutions because we are changing the order of the digits, so is the same:

75 + 57

than

57 + 75.

6 0
3 years ago
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