Answer:
ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.
Step-by-step explanation:
It is given that the triangle ABC is dilated to produce triangle A'B'C' with scale factor 3/4.
If a figure is dilated then preimage and image are similar.
If scale factor is between 0 to 1, then preimage is reduction of image.
If scale factor is more that 1, then preimage is enlargement of image.
If scale factor is 1, then preimage is congruent to the image.
We know that
So,
Therefore, the ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.
1: Subtract 168 from both sides
y-168=8x
2:divide both sides by 8
y-168/8 = x
3: just flip it over
x=168/8
Answer:?
Step-by-step explanation:
The solution to the problem is as follows:
Tan(sqrt(3)/3) * sqrt(3)/sqrt(3) = 1/sqrt (3)
therefore θ = 3 0 degrees = <span>Π/6
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