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stepan [7]
3 years ago
6

Find the solution to the equation below. 7f= 49 f=

Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0
The answer is f = 7. You divide both sides of the equation by 7
trapecia [35]3 years ago
5 0

Answer:

f = 7

Step-by-step explanation:

49/7 = 7

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Monthly sales of an SUV model are expected to increase at the rate of S′1t2 = -24t 1>3 SUVs per month, where t is time in mon
uysha [10]

The company will continue to manufacture this model for 19 months.

The question is ill-formatted. The understandable format is given below.

An SUV model's monthly sales are anticipated to rise at a rate of

S'(t)=-24^{1/3} SUVs each month, where "t" denotes the number of months and "S(t)" denotes the monthly sales of SUVs. When monthly sales of 300 SUVs are reached, the business intends to discontinue producing this model.

Find S if monthly sales of SUVs are 1,200 at time t=0 (t). How long will the business keep making this model?

Given S'(t)=-24^{1/3} ... ... (1)

Condition (1) at t=0; s(t) =1200

We find S(t)=300 then t=?

a) We find S(t)

from S'(t)=-24^{1/3}

\implies \frac{dS(t)}{dt}=-24t^{1/3} ~~[\because X'(t)=\frac{dX}{dt} \\\implies dS(t) = -24t^{1/3}dt\\

On Integrating both sides

S(t)=-18t^{4/3}+c ~...~...~(2)

Now, at t=0 then S(t)=1200

So, from (2)

1200=0+c

⇒c=1200

\thereforefrom eq (2)

S(t)=-18t^{4/3}+1200 ~...~...~(3)

b) Considering that the firm intends to cease production of this model once monthly sales exceed 300 SUVs.

So, take S(t)=300

from eq (2) 300=-18t^{4/3}+1200

t^{4/3}=\frac{1200-300}{18}\\=\frac{900}{18}=50\\\implies t=50^{3/4}\\\implies t=18.8030

Hence the company will continue 18.8020 months.

Learn more about integration here-

brainly.com/question/18125359

#SPJ10

8 0
2 years ago
In circle O below, AB is a diameter and m
Neko [114]

Answer:

i don't know

Step-by-step explanation:

i seriously don't know

4 0
3 years ago
Does this set of ordered pairs form a function?
zhenek [66]

Considering that each input is related to only one output, the correct option regarding whether the relation is a function is:

A. yes.

<h3>When does a relation represent a function?</h3>

A relation represents a function when each value of the input is mapped to only one value of the output.

For this problem, we have that:

  • The input is a number.
  • The output is an activity.

There are no repeated inputs, hence the relation is a function and option A is correct.

More can be learned about relations and functions at brainly.com/question/12463448

#SPJ1

3 0
2 years ago
Describe what a slope of -5 means in terms of x and y.
AlexFokin [52]
It means that you have to get a good one for the two weeks and you then have to get the two
6 0
3 years ago
Help me please emergency
adoni [48]

Step-by-step explanation:

this can be found by determination of the highest and lowest x values

4 0
2 years ago
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