The value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.
<h3>What is the value of sin (π/2)?</h3>
The value of sin (π/2) is equal to the number 1. The value of the sin-1(1) has to be find out.
Suppose the value of this function is <em>x</em>. Thus,

Solve it further,
......1
The value of sin (π/2) and -sin (-π/2) is equal to 1 such that,

Put this value in the equation 1,

Thus, the range will be,

Thus, the value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.
Learn more about the sine values here;
brainly.com/question/10711389
Ax + 32 = 6
- 32 = -32
---------------------
ax = -26
---- -----
a a
1x = -26
-----
a
x = -26
-----
a
Answer:
OD.(x-3)(x-2)
Step-by-step explanation:
we need two numbers (negative ir positive) that multiply to get 6 abd add to get -5.
so its OD
as -3×-2=6
and -3+-2=-5