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notsponge [240]
4 years ago
11

A merchant in Katmandu sells you a solid gold 6 kg statue for a very reasonable price. When you get home, you wonder whether or

not you got a bargain, so you lower the statue into a measuring cup and measure its volume. What volume will verify that it's pure gold?
Physics
1 answer:
Lilit [14]4 years ago
5 0

Answer:

0.000311 m³

Explanation:

The formula that connect volume, mass and density is given below

D = m/v ...................... Equation 1

Where D = Density of the gold, m = mass of the gold, v =  volume of the gold.

make v the subject of the equation

v = m/D .................. Equation 2

Given: m = 6 kg,

Note the density of pure gold = 19300 kg/m².

Substitute into equation 2

v = 6/19300

v = 0.000311 m³

Hence the volume that will verify that it's a pure gold = 0.000311 m³

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A cannon of mass 6.43 x 103 kg is rigidly bolted to the earth so it can recoil only by a negligible amount. The cannon fires a 7
Nata [24]

Answer:

The velocity of the shell when the cannon is unbolted is 500.14 m/s

Explanation:

Given;

mass of cannon, m₁ = 6430 kg

mass of shell, m₂ = 73.8-kg

initial velocity of the shell, u₂ = 503 m/s

Initial kinetic energy of the shell; when the cannon is rigidly bolted to the earth.

K.E = ¹/₂mv²

K.E = ¹/₂ (73.8)(503)²

K.E = 9336032.1 J

When the cannon is unbolted from the earth, we apply the principle of conservation of linear momentum and kinetic energy

change in initial momentum = change in momentum after

0 = m₁u₁ - m₂u₂

m₁v₁ = m₂v₂

where;

v₁ is the final velocity of cannon

v₂ is the final velocity of shell

v_1 = \frac{m_2v_2}{m_1}

Apply the principle of conservation kinetic energy

K = \frac{1}{2}m_1v_1^2 +  \frac{1}{2}m_2v_2^2\\\\K = \frac{1}{2}m_1(\frac{m_2v_2}{m_1})^2 + \frac{1}{2}m_2v_2^2\\\\K = \frac{1}{2}m_2v_2^2(\frac{m_2}{m_1}) + \frac{1}{2}m_2v_2^2 \\\\K = \frac{1}{2}m_2v_2^2 (\frac{m_2}{m_1} + 1)\\\\2K = m_2v_2^2 (\frac{m_2}{m_1} + 1)\\\\v_2^2 = \frac{2K}{M_2(\frac{m_2}{m_1} + 1)} \\\\v_2^2 = \frac{2*9336032.1}{73.8(\frac{73.8}{6430} + 1)}\\\\

v_2^2 = 250138.173\\\\v_2 = \sqrt{250138.173} \\\\v_2 = 500.14  \ m/s

Therefore, the velocity of the shell when the cannon is unbolted is 500.14 m/s

3 0
3 years ago
In a simple electric generator, a conducting loop of wire is placed in a magnetic field. The loop of wire is then rotated. Why i
kaheart [24]

Explanation:

If a coil of wire is placed in a magnetic field and rotated, an alternating (sinusoidal) current is induced. As it rotates, sometimes it is cutting through lots of magnetic flux, and so lots of current is

induced.

At other times, it is moving parallel to

the flux, and so no flux is cut, and no current is induced. In between, some current is induced. This creates an alternating current. Either end of the coil can be connected to wires outside of the generator in order to use the current elsewhere. This would be fine for the

first few rotations, but after this, the wires would get tangled up and the generator would be useless. To avoid this, we use a commutator. In an AC generator, this is a pair of rotating conducting 'slip rings' attached to either end of the coil. Carbon brushes bring these into contact with the outside world.

5 0
3 years ago
What do scientitsts do to easily share mesurment data they can understand
Leona [35]
There are a few ways to do this- unfortunately different fields are better at it than others! Medical research is generally pretty good, some other fields likewise very good, some not as much. Basically, though, what they do is use standadisation- they agree on the terminology, units of data, statistical measures, and so forth, that will be used in that scientific field. As much as possible, every scientist in the field uses those standards so everyone working in the field should recognise it. For instance, in clinical trials, there is very good agreement worldwide on what the different metrics we use are- e.g. in cancer research, we usually want to know the 5-year survival rate (meaning the percentage of patients still alive 5 years after diagnosis). So anyone with the right training should be able to pick up a clinical trial report and understand what the results are and what the report is saying.
6 0
3 years ago
A 700-kg car, driving at 29 m/s, hits a brick wall and rebounds with a speed of 4.5 m/s. If the car was in contact with the wall
Alinara [238K]

Answer:

<h2>57166.6N</h2>

Explanation:

Step one:

given data

mass=700kg

initial velocity u=29m/s

final velocity=4.5m/s

time t= 0.3second.

Step two:

The expression for the momentum is given as

FΔt=mΔv

make F subject of the formula

F=mΔv/Δt

Substitute our given data we have

F=700(29-4.5)/0.3

F=700*24.5/0.3

F=17150/0.3

F=57166.6N

the force is 57166.6N

6 0
3 years ago
How do you calculate acceleration
AfilCa [17]
A=f/m
Example a=10/2
A=5
7 0
4 years ago
Read 2 more answers
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