Question

A ball rolls up a ramp with a velocity of 8.0 m/s. How high up the ramp does it travel?

Answer 1

The greatest height the ball will attain is 3.27 m

Data obtained from the question

• Initial velocity (u) = 8 m/s

• Final velocity (v) = 0 m/s (at maximum height)

• Acceleration due to gravity (g) = 9.8 m/s²

• Maximum height (h) =?

The maximum height to which the ball can attain can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = 8² – (2 × 9.8 × h)

0 = 64 – 19.6h

Collect like terms

0 – 64 = –19.6h

–64 = –19.6h

Divide both side by –19.6

h = –64 / –19.6h

h = 3.27 m

Thus, the greatest height the ball can attain is 3.27 m

Learn more about motion under gravity:

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