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Anettt [7]
3 years ago
8

Pretend for a day your non-dominant hand is broken and you can’t use of it. Pay attention to the activities you do every day. Yo

u can even simulate a break by wrapping an ace bandage (not to tight) on your hand. What can you no longer do because of the loss in mobility? Imagine what patient’s must experience with long-term mobility loss. How would you have to adapt? How can you assist patients as an MA with mobility loss?
Physics
1 answer:
pantera1 [17]3 years ago
5 0
I would learn to use my other hand for doing stuff
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A series circuit has a voltage supply of 12 V and a resistor of 2.4 kΩ. How much power is dissipated by the resistor?
adell [148]

Answer:

(B) 0.06W

Explanation:

power absorbed by the resistor is given by \frac{V^2}{R}=I^2R

Where V = voltage

           R= resistance

            I =  current through the circuit

we have given V =12 Volt and resistance =2.4 K\Omega

current I=\frac{V}{R}=\frac{12}{2.4\times 1000}=5\times 10^{-3}A=5mA

power using voltage and resistance equation

p=\frac{12^2}{2.4\times 1000}=60mW =0.06W

using current equation P=I^2R=5^2\times 12=60mW= 0.06W

4 0
3 years ago
Conclusion for ohm law
kari74 [83]
Ohm’s Law states that electrical current is proportional to voltage and therefore inversely proportional to resistance - V = I x R
7 0
3 years ago
A car drives on a circular road of radius R. The distance driven by the car is given by = + [where a and b are constants, and t
pishuonlain [190]

Answer:

The question is incomplete, the complete question is "A car drives on a circular road of radius R. The distance driven by the car is given by d(t)= at^3+bt [where a and b are constants, and t in seconds will give d in meters]. In terms of a, b, and R, and when t = 3 seconds, find an expression for the magnitudes of (i) the tangential acceleration aTAN, and (ii) the radial acceleration aRAD3"

answers:

a.18a m/s^{2}

b. a_{rad}=\frac{(27a +b)^{2}}{R}

Explanation:

First let state the mathematical expression for the tangential acceleration and the radial acceleration.

a. tangential acceleration is express as

a_{tan}=\frac{d|v|}{dt} \\

since the distance is expressed as

d=at^{3}+bt

the derivative is the velocity, hence

V(t)=\frac{dd(t)}{dt}\\V(t)=3at^{2}+b\\

hence when we take the drivative of the velocity we arrive at

a_{tan}=\frac{dv(t)}{dt}\\ a_{tan}=6at\\t=3 \\we have \\a_{tan}=18a m/s^2

b. the expression for the radial acceleration is expressed as

a_{rad}=\frac{v^{2}}{r}\\a_{rad}=\frac{(3at^{2} +b)^{2}}{R}\\t=3\\a_{rad}=\frac{(27a +b)^{2}}{R}

4 0
3 years ago
Need asap!
Genrish500 [490]

Answer:

3.0 A Is the correct option

Explanation:

I = V / R

I = 12/ 4

= 3

7 0
3 years ago
The color red that we see depends upon the :
Anastaziya [24]

if i am correct the answer is d. because depending on how far a wavelength goes we see different colors.

7 0
4 years ago
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