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Anettt [7]
3 years ago
8

Pretend for a day your non-dominant hand is broken and you can’t use of it. Pay attention to the activities you do every day. Yo

u can even simulate a break by wrapping an ace bandage (not to tight) on your hand. What can you no longer do because of the loss in mobility? Imagine what patient’s must experience with long-term mobility loss. How would you have to adapt? How can you assist patients as an MA with mobility loss?
Physics
1 answer:
pantera1 [17]3 years ago
5 0
I would learn to use my other hand for doing stuff
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HACTEHA [7]

The volume of the object must be no larger than 11.15 m^3.

Explanation:

In order for an object to be able to float in water, its density must be equal or smaller than the water density.

The density of water is:

\rho = 1000 kg/m^3

This means that the density of the object must be no larger than this value.

We also know that the density of an object is given by

\rho = \frac{m}{V}

where

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V is its volume

For the object in this problem, the mass is

m=1.115\cdot 10^4 kg

Therefore, we can re-arrange the equation to find its volume:

V=\frac{m}{\rho}=\frac{1.115\cdot 10^4}{1000}=11.15 m^3

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kogti [31]

Answer:

3 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 2 L

Initial pressure (P₁) = 0.75 atm

Final pressure (P₂) = 0.5 atm

Final volume (V₂) =?

Using the Boyle's law equation, the new volume (i.e final volume) of the Ne gas can be obtained as:

Initial volume (V₁) = 2 L

Initial pressure (P₁) = 0.75 atm

Final pressure (P₂) = 0.5 atm

Final volume (V₂) =?

P₁V₁ = P₂V₂

0.75 × 2 = 0.5 × V₂

1.5 = 0.5 × V₂

Divide both side by 0.5

V₂ = 1.5 / 0.5

V₂ = 3 L

Thus, the new volume of the Ne gas is 3 L

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nirvana33 [79]
Water is not wet, wet is a state of being. Water, however, can make things wet.
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