The answer is Providing national parks
Answer:
The frequency of the wheel is the number of revolutions per second:
f= \frac{N_{rev}}{t}= \frac{10}{1 s}=10 Hz
And now we can calculate the angular speed, which is given by:
\omega = 2 \pi f=2 \pi (10 Hz)=62.8 rad/s in the clockwise direction.
Explanation:
72 Km/hr
= 72000 m/ 60×60 s
= 72000 m/ 3600 s
= 20 m/s
Answer is 20 m/s.
Hope it helps! Please do comment
The angular speed of the playground ride is determined as 0.3 rad/s.
<h3>
What is angular speed?</h3>
Angular speed is the rate at which an object changes it angles which we measure in radians in a given time.
<h3>
Angular speed of the ride</h3>
The angular speed of the ride if the ride makes one complete revolution is calculated as follows;
ω = θ/t
ω = 2π/t
where;
- ω is angular speed of the ride
- t is time of motion of the ride
one complete revolution = 2π radians
ω = 2π/21
ω = 0.3 rad/s
Thus, the angular speed of the playground ride is determined as 0.3 rad/s.
Learn more about angular speed here: brainly.com/question/24158647
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The complete question is below;
A playground ride requires 21 seconds to make one complete revolution, what is angular speed of the ride in radian per second.
<span>As long as both mirrors are set at 45% and the same size then you see the same as is reflected in the upper mirror </span>
<span>Put a lens in the middle of the tube </span>
<span>? </span>
<span>We use mirrors when we drive cars ect </span>
<span>Normally they are set across from a concealed entrance or one that is hard to see both ways like the inside of a hairpin bend. Sometimes only to help in one direction. </span>
<span>Sonar which is sound waves that are sent out at a set rate then reflected by objects. The longer the gap between the two the further away it is, They still use periscopes to target boats though. </span>
<span>The periscope can only reflect what is outside so if you could see it because there is enough light then Yes. If you could not see it because it is dark then No unless you get into Info-Red light or Image Intensifying systems as well </span>