We need the total count of persons = 10+12+12+15 = 49 persons
We need the count of the target group, female or teaching assistants
= (10+12) professors + 12 male teaching assistants
= 22+12
= 34 persons
Assuming equal probability of choosing anyone from the 30 persons, the
probability of choosing a professor or a male
= 34/49
(For probability calculations, try to keep a fraction for as long as you can, because fractions are exact. Decimal are frequently approximate, for example in this case, 34/49=0.693877551020...... = 0.694 approximately)
X = number of correct answers
Y = number of incorrect answers
School A has 174 points and school B has 102 points.
A = 174
B = 102
School A has the same number of correct and incorrect answers during the final round.
A = 174 + 10X - 6Y
School B gives no incorrect answers and the same number of correct answers as school A.
B = 102 + 10X
The contest ends with the two schools tied.
Score = 174 + 10X - 6Y = 102 + 10X
174 + 10X - 6Y = 102 + 10X
The answer is 2.5 plus the sum of 1000
Answer:
x>
.
x>\frac{53}{6}
Step-by-step explanation:
12x>140−34
2 Simplify 140-34140−34 to 106106.
12x>106
12x>106
3 Divide both sides by 1212.
x>\frac{106}{12}
(94.50 - 18.50) ÷ f = a
f=family members
a=answer
I don't know how many family members there are, but you would just replace f with the amount.
