Answer:
308.2 g of NH₃.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
3H₂ + N₂ —> 2NH₃
Next, we shall determine the mass of N₂ that reacted and the mass of NH₃ produced from the balanced equation. This can be obtained as follow:
Molar mass of N₂ = 2 × 14 = 28 g/mol
Mass of N₂ from the balanced equation = 1 × 28 = 28 g
Molar mass of NH₃ = 14 + (3×1)
= 14 + 3 = 17 g/mol
Mass of NH₃ from the balanced equation = 2 × 17 = 34 g
Summary:
From the balanced equation above,
28 g of N₂ reacted to produce 34 g of NH₃.
Finally, we shall determine the mass of NH₃ produced by the reaction of 253.8 g of N₂. This can be obtained as illustrated below:
From the balanced equation above,
28 g of N₂ reacted to produce 34 g of NH₃.
Therefore, 253.8 g of N₂ will react to produce = (253.8 × 34)/28 = 308.2 g of NH₃.
Thus, 308.2 g of NH₃ were obtained from the reaction.
