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2 years ago

Does plateau have low elevation

Chemistry

1 answer:

denis-greek [22]2 years ago

8 0

Answer:

No it does not, plateaus are very elevated

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Which adaptation is likely to increase the chances of survival of an animal in a rainforest?

LiRa [457]

I know I think it’s a A

6 0

3 years ago

This diagram shows the basis for forming which of the following

Elza [17]

(I didn't have this as a question on any of my quizzes, but I will try my best. I wish you luck!)

Answer: Proteins

This is a peptide bond, which is a bond that forms between two amino acids through a condensation reaction. Amino acids make proteins.

5 0

1 year ago

Calculate the mass of iron(III) oxide that contains a million iron atoms. Be sure your answer has a unit symbol if necessary, an

KiRa [710]

Answer: The mass of iron (II) oxide that contains a million iron atoms is $2.6\times 10^{-17}g$

Explanation:

We are given:

Number of iron atoms = A million = $1.0\times 10^6$

The chemical formula of the given compound is $Fe_2O_3$

It is formed by the combination of 2 iron atoms and 3 oxygen atoms.

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

1 mole of iron (II) oxide will contain = $(2\times 6.022\times 10^{23})=1.2044\times 10^{24}$ number of iron atoms

We know that:

Molar mass of iron (II) oxide = 159.7 g/mol

Applying unitary method:

For $1.2044\times 10^{24}$ number of iron atoms, the mass of iron (II) oxide is 159.7 g

So, for $1.0\times 10^6$ number of iron atoms, the mass of iron (II) oxide will be $\frac{159.7}{1.2044\times 10^{24}}\times 1.0\times 10^6=2.6\times 10^{-17}g$

Hence, the mass of iron (II) oxide that contains a million iron atoms is $2.6\times 10^{-17}g$

8 0

3 years ago

The density of iron= 7.86 g/cm^3, what is the volume of 150g of iron

nadezda [96]

Answer: 19.08 cm^3

Explanation:

Density = mass/vol (Rearrange to solve for vol)

Vol = mass/density

Vol = 150/7.86 = 19.08 cm^3

7 0

3 years ago

4NH3+5O2=4NO+6H20 if 32.5 grams of NH3 react with enough oxygen, how many grams of water should form?

Aneli [31]

51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.

<h3>How to find the Number of moles ?</h3>

To calculate the number of moles use the formula

Number of moles = $\frac{\text{Given Mass}}{\text{Molar Mass}}$

= $\frac{32.5}{17}$

= 1.9 mol

4NH₃ + 5O₂ → 4NO + 6H₂O

4 mol of NH₃ react with oxygen to given 6 mole of water.

So 1.9 mol of NH₃ produces = $\frac{1.9}{4}\times 6$

= 2.85 mol of water

Mass of water = Molar Mass of water × Number of moles of water

= 18 × 2.85

= 51.3 gram

Thus from the above conclusion we can say that 51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.

Learn more about the Moles here: brainly.com/question/15356425

#SPJ1

6 0

1 year ago