The given question is incomplete. The complete question is:
Suppose a current of 0.920 A is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for 47.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.
Answer: 0.0484 g
Explanation:
where Q= quantity of electricity in coloumbs
I = current in amperes = 0.920 A
t= time in seconds = 47.0 sec

96500 Coloumb of electricity electrolyzes 1 mole of Ag
43.24 C of electricity deposits =
of Ag
Thus the mass of pure silver deposited on a metal object made into the cathode of the cell is 0.0484 g
Answer:
By electroplating
Explanation:
The metal which requires to be protected from rust is connected to the anode while a lower metal in the series is connected to the cathode, the a complete circuit is made and current is passed through the circuit there by resulting to the coating of the metal at the anode.
Answer:
first number is the correct answer
The mitosis is the cell division so it both B and C