Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
G(x) would have to be -->7 units.
The relationship between f(x) and s(x) where s(x)=af(x-b)+z is that g(x) is f(x) stretched by the reciprocal of a, b is the liar (all x values go up if b goes down and visa versa), and it moves up z units.
Answer:
Math is confusing
Step-by-step explanation:
LOL
6 mm
Set up a proportion of 12/9=8/x. Cross multiply and this gives us 12x=72. Now divide both sides by 12 and you get 6.
Subtract 13 from both sides.
-13
-7 = -20
-2x = -20
Divide by 2 on both sides.
Remember: Negative divided by a negative makes a positive.
-2/-2 = 1
-20/-2 = 10
Your answer:
x = 10
