Hector placed new floor tile in his regular kitchen. The kitchen is 9 feet 9 inches long and 7 feet 4 inches wide. Hector paid $ 50 for tiles to cover the entire floor. What was the cost to tile each square foot of his kitchen? Round your answer to the nearest cent.
1 answer:
Answer:
29cents
Step-by-step explanation:
Given the dimension of the Kitchen as;
Length = 9feet 9inches
Width = 7feet 4inches
Since 1inch = 0.833ft
Length = 9+(9×0.833) = 9+7.497=16.497feet
Width = 7+(4×0.833) = 7+3.332 = 10.332feet
Area of the kitchen in ft² = 16.497×10.332= 170.447004ft²
Since Hector pays $50 to cover the floor, hence;
$50 = 170.447004ft²
x = 1ft²
Cross multiply
170.447004x= 50
x = 50/170.447004
x= $0.2933
x = 29.33cents
Cost of each square foot of his kitchen will be 29cents to nearest cent
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