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goldenfox [79]
3 years ago
12

PLEASE HELP ASAP I WILL GIVE THANKS TO WHOEVER ANSWER IT RIGHT JUST PLS HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry
2 answers:
Cerrena [4.2K]3 years ago
8 0

Answer:

Mars has an orbit with a semimajor axis of 1.524 astronomical units (228 million km), and an eccentricity of 0.0934 The planet orbits the Sun in 687 days and travels 9.55 AU in doing so making the average orbital speed 24 km/s.

The eccentricity is greater than that of every other planet except Mercury, and this causes a large difference between the aphelion and perihelion distances—they are 1.6660 and 1.3814 AU

Explanation:

Radda [10]3 years ago
3 0

Answer: i hope this helps :)

-- 687 days

-- After years of analysis, Kepler discovered that Mars's orbit was likely to be an ellipse, with the Sun at one of the ellipse's focal points. This, in turn, led to Kepler's discovery that all planets orbit the Sun in elliptical orbits, with the Sun at one of the two focal points.

-- From our point of view as we race around the Sun, Mars is falling behind; consequently, we see Mars moving in a retrograde direction from night to night across the sky. Since the Earth always moves around the Sun faster than Mars, you might imagine that Mars's motion will always be retrograde.

-- Basically, that planets do not move with constant speed along their orbits. Rather, their speed varies so that the line joining the centers of the Sun and the planet sweeps out equal parts of an area in equal times. The point of nearest approach of the planet to the Sun is termed perihelion

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2 AgNO3(aq) + CaCl2(aq) -----> 2 AgCl(s) + Ca(NO3)2(aq)
yan [13]

5.732 grams of AgCl is formed when 0.200 L of 0.200 M AGNO3 reacts with an excess of CaCl2.

Explanation:

The balanced equation:

2 AgNO3(aq) + CaCl2(aq) -----> 2 AgCl(s) + Ca(NO3)2(aq)

data given:

volume of AgNO3 = 0.2 L

molarity of AgNO3 = 0.200 M

atomic weight of AgCl= 143.32 gram/mole

from the formula, number of moles can be calculated

Molarity = \frac{number of moles}{volume in litres}

number of moles of AgNO3 = 0.04

From the reaction:

2 moles of AgNO3 reacts to form 2 moles of AgCl

0.04 moles of AgNO3 reacts to form x mole of AgCl

\frac{2}{2} = \frac{x}{0.04}

= 0.04 moles of AgCl is formed

mass of AgCl formed is calculated by multiplying number of moles with atomic mass of AgCl

mass of AgCl = 0.04 x 143.32

                       = 5.732 grams of AgCl is formed.

4 0
3 years ago
Lithium bettery structure<br> and better charge rate
Zolol [24]
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A 4.98g sample of aniline (C6H5NH2, molar mass is 93.13g/mol) was combusted in a bomb calorimeter with a heat capacity of 4.25kJ
natima [27]

 the value  of  delta H°  for aniline = -3201. 5   Kj/mol


<u><em> calculation</em></u>

 Step 1: find heat

Q ( heat)  =  C  ( specific heat capacity)  x ΔT  ( change in temperature)

  C= 4.25 kj/c°

 ΔT = 69.8-29.5  = 40.3 c°

 Q= 4.25 kj/c    x  40.3 c = 171.28 kj

Step 2:  find the moles of aniline

  moles  = mass/ molar  mass

 = 4.98 g/ 93.13 g/mol =0.0535  moles

Step 3 :  find delta H

 171.28 kj   / 0.0535=3201.5 kj/mol


since the reaction is  exothermic  delta  H = -3201.5 Kj/mol

 


3 0
3 years ago
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