KCl + H2O
because acid + base gives salt and water
10 mL of 0.1 M NaOH is equal to 1 equivalent of base, if titrating 10.00 mL of 0.1 M amino acid.
Given :
0.1 M NaOH
0.1 M Amino acid
10.00 mL volume of Amino acid
<em> R-CH(NH₂)-COOH + NaOH → R-CHNH₂Na + H₂O</em>
In this case, end factor = 1 and It is 1 mole / 1 mole ratio
Since, the concentration of amino acid and NaOH are same, that is 0.1 M.
Concentration of amino acid = concentration of NaOH
0.1 M = 0.1 M
Therefore, 10 mL of NaOH is required to neutralize 10 mL of amino acid and the end factor is equivalent to 1.
Hence, The volume of 0.1 M NaOH is equal to 1 equivalent of base.
To learn more about titration,
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<span>the balanced equation for the reaction is as follows
Na</span>₂<span>SO</span>₄<span> + BaCl</span>₂<span> ----> 2NaCl + BaSO</span>₄
<span>stoichiometry of Na</span>₂<span>SO</span>₄<span> to BaCl</span>₂<span> is 1:1
first we need to find out which the limiting reactant is
limiting reactant is fully used up in the reaction.
number of Na2So4 moles - 0.5 mol number of BaCl2 moles - 60 g / 208 g/mol = 0.288 mol
since molar ratio is 1:1 equal number of moles of both reactants should react with each other
therefore BaCl2 is the limiting reactant and Na2SO4 is in excess. amount of product formed depends on number of limiting reactant present.
stoichiometry of BaCl</span>₂<span> to BaSO</span>₄<span> is 1:1.
therefore number of BaSO4 moles formed - 0.288 mol</span>
Answer: Tetonic plates
Explanation: just because