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OlgaM077 [116]
3 years ago
12

A 4.98g sample of aniline (C6H5NH2, molar mass is 93.13g/mol) was combusted in a bomb calorimeter with a heat capacity of 4.25kJ

/°C. If the temperature rose from 29.5°C to 69.8°C, determine the value of delta H°comb for aniline
Chemistry
1 answer:
natima [27]3 years ago
3 0

 the value  of  delta H°  for aniline = -3201. 5   Kj/mol


<u><em> calculation</em></u>

 Step 1: find heat

Q ( heat)  =  C  ( specific heat capacity)  x ΔT  ( change in temperature)

  C= 4.25 kj/c°

 ΔT = 69.8-29.5  = 40.3 c°

 Q= 4.25 kj/c    x  40.3 c = 171.28 kj

Step 2:  find the moles of aniline

  moles  = mass/ molar  mass

 = 4.98 g/ 93.13 g/mol =0.0535  moles

Step 3 :  find delta H

 171.28 kj   / 0.0535=3201.5 kj/mol


since the reaction is  exothermic  delta  H = -3201.5 Kj/mol

 


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1. the purpose of the aqueous solutions in a galvanic cell is to?
ludmilkaskok [199]

Answer:

1. The correct option is;

c. maintains charge balance in the cell

2. The correct option is;

c. +3.272 V

Explanation:

The aqueous solution in a galvanic cell is the electrolyte which is a ionic solution containing that permits the transfer of ions between the separated compartment of the galvanic cell such that the overall system is electrically neutral

Therefore, the aqueous solution maintains the charge balance in the cell

2. Here we have;

B₂ + 2e⁻ → 2B⁻ Ecell = 0.662 V

A⁺ + 1e⁻ → A Ecell = -1.305 V

Hence for the overall reaction, we have;

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5 examples of Earth Surface .<br>​
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<em>lithosphere</em><em> </em><em>(land)</em>

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6 0
2 years ago
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Which of the following equations best represents the meaning of the law of conservation of mass?
nalin [4]

The correct answer is a mass of products = mass of reactants.  

In a chemical reaction, the law of conservation of mass states that the entire mass of reactants is equivalent to the entire mass of products. For example, the mass of sodium and the mass of chlorine, which reacts with the sodium is equivalent to the product sodium chloride's mass. As in the chemical reaction, the atoms are only rearranged, there must be an equal number of chlorine and sodium atoms in both the products and the reactants.  


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3 years ago
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The normal boiling point of liquid methyl acetate is 331 K. Assuming that its molar heat of vaporization is constant at 30.6 kJ/
horsena [70]

Answer:

T_2=338.9026K

Boiling point of CH3COOCH3 at external pressure is 338.9026K

Explanation:

We are going to use Clausius-Clapeyron Equation:

ln\frac{P_2}{P_1} =-\frac{\Delta H}{R}(\frac{1}{T_2}-\frac{1}{T_1})

Where:

P_2 is the external pressure

P_1 is the atmospheric Pressure=1 atm

ΔH is the heat of vaporization

T_2  boiling point of CH3COOCH3 at external pressure

T_1 normal boiling point of liquid methyl acetate

Now:

\frac{1}{T_2}=-ln\frac{P_2}{P_1}*\frac{R}{\Delta H}+\frac{1}{T_1} \\\frac{1}{T_2}=-ln\frac{1.29}{1}*\frac{8.314}{30.6*10^3}+\frac{1}{331} \\\frac{1}{T_2}=2.9507*10^-^3\\T_2=\frac{1}{2.9507*10^-^3} \\T_2=338.9026K

Boiling point of CH3COOCH3 at external pressure is 338.9026K

5 0
3 years ago
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