Reactants are NaHCO3 and HC2H3O2 because they are on the left side of the arrow, aka they’re what’s going in to make the products. NaC2H3O2, H2O and CO2 are the products bc they’re on the right side of the arrow, aka they are the results of the reactants combining
<span>Balancing the choices, we have as follows:
A. 3AgBr + GaPO4 → Ag3PO4 +GaBr3
B. 3H2SO4 + 2B(OH)3 → B2(SO4)3 + 6H2O
C. Fe + 2AgNO3 → Fe(NO3)2 + 2Ag
D. C2H4O2 +2O2 → 2CO2 + 2H2O
Therefore, the correct answers are option A and B. Hope this answers the question. Have a nice day.</span>
Answer: 30 °C
Explanation:
86 degrees Fahrenheit = 30 degrees Celsius
86°f to degrees Celsius is 30°c.
Answer:
You determine the weighted averages if the individual isotopic masses.
Procedure:
The atomic mass of Si is the <em>weighted average </em>of the atomic masses of its isotopes.
We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its percent abundance).
The three stable isotopes of Si are Si-28 (27.98 u, 92.22 %), Si-29 (28.98 u, 4.69 %), and Si-30 (29.97 u, 3.09 %).
Set up a table for easy calculation.
0.9222 × 27.89 u = <em>x</em> u
0.0469 × 28.98 u = <em>y</em> u
0.0309 × 29.97 u = <em>z</em> u
TOTAL = (<em>x</em>+<em>y</em>+<em>z</em>) u = atomic mass of Si.
Answer:
Na is the element from the second period that has the largest atomic radius
Explanation:
The atomic radius is a chemist property from the periodic table. It is decreased when we move in a period from the periodic, so the element in the second period that has the largest radius is Na, and the shortest, the Ar
The atomic radius indicates the distance between the nucleus and the outermost valence layer. In the periods it decreases with increasing Atomic Number, to the right, due to the attraction that the nucleus exerts on the electrons of the outermost orbitals, thus decreasing the core-electron distance.
