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omeli [17]
3 years ago
8

Which statement best explains the energy change that will occur when the

Chemistry
2 answers:
ludmilkaskok [199]3 years ago
7 0

Answer:

D. The ball will transfer kinetic energy to the catcher's mitt.

I just took the exam for this :)

amid [387]3 years ago
5 0

Answer:the answer is D

Explanation:

I have already taken the exam. Hope this helps

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Elena L [17]

Answer:

no it should not that place is historical and so they should make where u can visit but protect it as a historical landmark

3 0
3 years ago
Does this sound catchy or invite you to read more? "GMOs and pesticides are general amongst farmers for generations and should n
siniylev [52]

Answer:

It sounds fine, but it may be a bit too long. It's difficult to shorten things like this, but getting more straight to the point would give it that "catchy" feel.

Explanation:

3 0
3 years ago
A graph that demonstrates the amount of substance that dissolve in given quantity of solvent st specificied conditions
Basile [38]

Answer:

Beef curtains

Explanation:

8 0
3 years ago
Read 2 more answers
What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.
AlekseyPX

Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

pH=pK_{a} + log(\frac{[Base]}{[Acid]})

According to the given conditions, the equation will become as follow

pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

Placing all the given data we obtain,

pH=6.86 + log(\frac{0.058}{0.042})

pH=7.00

5 0
3 years ago
What is the net Ionic equation of HClO4(aq)+ NaOH(aq) = H2O(l)+ NaClO4(aq)
uranmaximum [27]
H^+(aq) + OH^-(aq) ---> H2O(l) 

<span>Na^+ and ClO4^- are the spectator ions.</span>
7 0
3 years ago
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