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Wewaii [24]
3 years ago
13

Calnexin and calreticulin catalyze the removal of the final glucose residue from glycoproteins during the folding process. True

or False Transketolase transfers two carbon units in the pentose phosphate pathway using a thiamine pyrophosphate cofactor. True or False In theory, chloroplasts should only absorb 8 photons per oxygen molecule evolved during photosynthesis, but they actually absorb more than 8 photons per evolved oxygen molecule. True or False Fructose-2,6-bisphosphate activates both phosphofructokinase and fructose bisphosphatase to increase flux through gluconeogenesis. True or False The Calvin cycle shares enzymes that are homologous to enzymes involved in glycolysis, gluconeogenesis, and the pentose phosphate pathway with only three enzymes unique to the Calvin cycle. True or False
Chemistry
1 answer:
zloy xaker [14]3 years ago
8 0

Answer:

Explanation:

A) False.

Glucosidase (not calnexin nor calreticulin) helps to remove glucose residue.

Both calnexin and calreticulin rather have an affinity for last glucose residue of misfolded protein (Only misfolded proteins are marked by glycosyltransferase by attaching glucose residue). They attach with misfolded protein and with the help of other proteins like ERp57 (a type of protein disulfide isomerase) and try to fold it properly. If protein is properly folded then glucosidase removes the glucose residue thereby releasing the properly folded protein from calnexin or calreticulin. and now protein is transported to the Golgi body. If folding is still not proper then the same cycle of glycosylation -binding of calnexin/calreticulin and effort to fold it properly is repeated.

B) True.

Transketolase is a key enzyme of the pentose phosphate pathway. It contains thiamine diphosphate (TPP) as a cofactor. it does transfer 2 carbon residue from a ketose to aldose. So, effectively it converts one ketose sugar to aldose with 2 carbonless and aldose to ketose with 2 carbon more.

C) True.

Theoretically, for the evolution of one molecule of oxygen, only 8 photons are required. But in practice, it is known that there are many variants like wavelength and the energy of the photon. The larger the wavelength, like the one which is used in PS1 (more than 700nM), the lesser the energy. Secondly, the energy of the photon is also wasted as heat energy. Because of these factors, more than 8 photons are needed in reality.

D) Wrong.

Fructose 2,6 bisphosphate is a key substrate and affects both the enzymes- phosphofructokinase and fructose bisphosphatase allosterically during gluconeogenesis. It strongly favors the breakdown of glucose during glycolysis by activating phosphofructokinase but it inhibits fructose bisphosphatase. Hence it activates the kinase enzyme while inhibiting the phosphatase and maintains a huge supply of glucose in the system.

E) Wrong.

The Calvin cycle shares similarity with the pentose phosphate pathway as both are involved in the synthesis of sugar (Triose and Ribose). However, it does not share similarity with enzymes of glycolysis (which is primarily focused on the breakdown of glucose) and gluconeogenesis.

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5 0
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coldgirl [10]
Empirical formula is the simplest ratio of whole numbers of components in a compound 
calculating for 100 g of compound 
                                             C                             H                             O
mass                                  64.27 g                   7.19 g                     28.54 g
number of moles        64.27 g / 12 g/mol      7.19 g/1 g/mol     28.54 g / 16 g/mol 
                                        = 5.356 mol           = 7.19 mol           = 1.784 mol 
divide by least number of moles  
                                     5.356 / 1.784            7.19 / 1.784         1.784 / 1.784
                                      = 3.002                     4.03                     = 1.000
rounded off to nearest whole number 
 C - 3
 H - 4
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empirical formula - C₃H₄O
 
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molecular formula is the actual ratio of elements making up the compound 
number of empirical units = molar mass of molecule / empirical mass
      empirical units = 168.19 g/mol  / 56 g = 3.00
there are 3 empirical units making up the molecular formula 
molecular formula = 3 x C₃H₄O

molecular formula = C₉H₁₂O₃

                 
5 0
4 years ago
Consider the following reaction: 2HI(aq)+Ba(OH)2(aq) → 2H2O(l)+BaI2(aq) Enter the complete ionic equation for this reaction. Exp
babunello [35]

Answer:

2 HI(aq) + Ba²⁺(aq) + 2 OH⁻(aq) → 2 H₂O(l) + Ba²⁺(aq) + 2I⁻(aq)

Explanation:

Let's consider the following balanced molecular equation.

2 HI(aq) + Ba(OH)₂(aq) → 2 H₂O(l) + BaI₂(aq)

In the complete ionic equation we include all the ions and the species that do not dissociate in water. HI is a weak electrolyte so it exists mostly in the molecular form. H₂O has a very low equilibrium constant (Kw = 10⁻¹⁴) si it exists mainly in the molecular form.

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3 0
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AnnZ [28]

Answer: Option (A) is the correct answer.

Explanation:

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Now, when we double the depth then it means H is increasing 2 times and then the above relation will be as follows.

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Now, dividing equation (1) by equation (2) as follows.

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Cancelling the common terms we get the following.

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Thus, we can conclude that if doubled the depth of the dam the hydrostatic force will be 4F.

4 0
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