Answer:
The rest of the food chain will not have as much to eat and will decrease in population and the decomposers will grow in population because the rest of the creatures will die and give the decomposers more food
Explanation:
The mass, in grams, of hydrogen that would be produced from the reaction will be 0.102 grams
<h3>Stoichiometric calculations</h3>
From the balanced equation of the reaction:
The mole ration of magnesium to water is 1:2.
Mole of 4.73 grams Mg = 4.73/24.3 = 0.195 moles
Mole of 1.83 grams water = 1.83/18 = 0.102 moles
Hence, water is limiting.
Mole ratio of water to the hydrogen produced = 2:1
Equivalent mole of hydrogen gas produced = 0.102/2 = 0.05 moles
Mass of 0.05 moles hydrogen gas = 0.05 x 2 = 0.102 grams
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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Answer:
a. NH3 is limiting reactant.
b. 44g of NO
c. 40g of H2O
Explanation:
Based on the reaction:
4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l)
4 moles of ammonia reacts with 5 moles of oxygen to produces 4 moles of NO and 6 moles of water.
To find limiting reactant we need to find the moles of each reactant and using the balanced equation find which reactant will be ended first. Then, with limiting reactant we can find the moles of each reactant and its mass:
<em>a. </em><em>Moles NH3 -Molar mass. 17.031g/mol-</em>
25g NH3*(1mol/17.031g) = 1.47moles NH3
Moles O2 = 4 moles
For a complete reaction of 4 moles of O2 are required:
4mol O2 * (4mol NH3 / 5mol O2) = 3.2 moles of NH3.
As there are just 1.47 moles, NH3 is limiting reactant
b. Moles NO:
1.47moles NH3 * (4mol NO/4mol NH3) = 1.47mol NO
Mass NO -Molar mass: 30.01g/mol-
1.47mol NO * (30.01g/mol) = 44g of NO
c. Moles H2O:
1.47moles NH3 * (6mol H2O/4mol NH3) = 2.205mol H2O
Mass H2O -Molar mass: 18.01g/mol-
2.205mol H2O * (18.01g/mol) = 40g of H2O
The first word could be: pairs and the second: relax
To find joules (heat) we use the following formula
heat= mass x specific heat x ΔT
mass= 72.5 grams
specific heat (Water)= 4.184 j/g·C
ΔT= 95 - 28= 67 °C
heat= (72.5 grams) (4.18 j/g·C) (67°C)= 20300 joules or 20.3 Kilojoules