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DochEvi [55]
3 years ago
10

Calculate the coulombic force (in Newtons) felt by an electron and a proton separated by a distance of 1 angstrom. An angstrom i

s 10−10 meters.
Chemistry
1 answer:
spayn [35]3 years ago
7 0
F=kq'q"/d²


charge of electron(q')= 1.6022*10^-19
charge of proton (q")= -1.6022*10^-19
Coulomb's constant (k)= 9*10^9
distance (d)=10^-10

substituting values into equation

F= (9*10^9)*(1.6022*10^-19)(-1.6022*10^-19)/(10^10)²

F= -2.31034036 × 10^-48N
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A certain first-order reaction 45% complete in 65seconds, determine the rate constant and the half life for the process ​
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The rate constant : k = 9.2 x 10⁻³ s⁻¹

The half life : t1/2 = 75.3 s

<h3>Further explanation</h3>

Given

Reaction 45% complete in 65 s

Required

The rate constant and the half life

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A = 0.55

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ln 0.55 = -k.65 + ln 1

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k = 9.2 x 10⁻³ s⁻¹

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1- The correct answer is C :


the elements arranged in the modern periodic table by increasing atomic number.


The explanation:


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2- The correct answer is C:


strontium, magnesium, calcium, beryllium are the elements which have similar properties.


The explanation:

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5- The correct answer is B:


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