It is ABCD ~ GFHE because you have to list corresponding points when stating similarity
L=Lim tan(x)^2/x x->0
Since both numerator and denominator evaluate to zero, we could apply l'Hôpital rule by taking derivatives.
d(tan^2(x))/dx=2tan(x).d(tan(x))/dx = 2tan(x)sec^2(x)
d(x)/dx = 1
=>
L=2tan(x)sec^2(x)/1 x->0
= (2(0)/1^2)/1
=0/1
=0
Another way using series,
We know that tan(x) = x+x^3/3+2x^5/15+.....
then tan^2(x), using binomial expansion gives
x^2+2*x^4/3+.... (we only need two terms)
and again apply l'Hôpital's rule, we have
L=d(x^2+2x^4/3+...)/d(x) = (2x+8x^3/3+...)/1
=0 as x->0
(x+1) x (3x-4) is the answer
<span>Find the inverse function of f.
f(x)=(1+3x)/(5-2x)
Interchange x and y to get:
x=(1+3y)/(5-2y)
Solve for y as follows:
5x-2xy=1+3y
3y+2xy=5x-1
y(3+2x)=5x-1
y=(5x-1)/(2x+3)
this is the inverse function</span>
This means 21g is 100-16%=84%.
21x0.16=3.36
21+3.36=24.36
