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Amanda [17]
3 years ago
7

How do you find the area and perimeter of a rectangle. And how do you find the area and perimeter of a square?

Mathematics
1 answer:
cupoosta [38]3 years ago
5 0

Answer:

The perimeter of a rectangle is P = 2 b + 2 h , where is the base (or width) and is the height (or length). If a rectangle is a square, with sides of length , the formula for perimeter is P s q u a r e = 2 s + 2 s = 4 s and the formula for area is A s q u a r e = s ⋅ s = s 2

Step-by-step explanation:

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Erika and Bradley want to hike the big cypress trail. they will hike a total of 75 miles. If Erika and Bradley plan to hike for
ahrayia [7]
They will hike 6.25 miles a day

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3 years ago
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the volume of hemisphere is 1527.4cm^3.find the radius of the hemisphere to the nearest whole whole number.(take π to be 22/7)​
skelet666 [1.2K]

Answer:

radius of the hemisphere = 9 cm approx

Step-by-step explanation:

Volume of hemisphere = \frac{2}{3} \pi r^{3}

1527.4 = \frac{2}{3} * \frac{22}{7} * r^{3}

\frac{7*15274*3}{2*22*10} = r^{3}

\frac{320754}{440} = r^{3}

r^{3} = 729

r = \sqrt[3]{729}

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6 0
3 years ago
kayla is drawing a picture of her favorite building in her city, the height of the building on her drawing is 3 inches tall, the
Stolb23 [73]

Answer:

1/12

Step-by-step explanation:

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4 0
3 years ago
Please help for this question
kogti [31]
First you need to subtract the 29 and the 8 - equals 21
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8 0
3 years ago
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Prove algebraically that the straight line with equation x=2y+5 is a tangent to the circle with equation x^2+y^2=5
zmey [24]

Differentiate both sides of the equation of the circle with respect to x, treating y=y(x) as a function of x:

x^2+y^2=5\implies2x+2y\dfrac{\mathrm dy}{\mathrm dx}=0\implies\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac xy

This gives the slope of any line tangent to the circle at the point (x,y).

Rewriting the given line in slope-intercept form tells us its slope is

x=2y+5\implies y=\dfrac12x-\dfrac52\implies\mathrm{slope}=\dfrac12

In order for this line to be tangent to the circle, it must intersect the circle at the point (x,y) such that

-\dfrac xy=\dfrac12\implies y=-2x

In the equation of the circle, we have

x^2+(-2x)^2=5x^2=5\implies x=\pm1\implies y=\mp2

If x=-1, then -1=2y+5\implies y=-3\neq2, so we omit this case.

If x=1, then 1=2y+5\implies y=-2, as expected. Therefore x=2y+5 is a tangent line to the circle x^2+y^2=5 at the point (1, -2).

7 0
4 years ago
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