A shopping cart that has a mass of 2 kilograms is being pushed with a

Ghee freezes from bottom but water freezes from top, why?

zhenek [66]

I presume you mean ghee as in the butter. Seen as ice is one of the many solids to have a lower density than its liquid form, it freezes from the top. Ghee is made from hydrocarbons not dissimilar to petroleum, it shares the same properties as most elements of its solid state (at 1 atmosphere) being at a higher density than its liquid state.

8 0

3 years ago

Which picture correctly shows the path of refracted light rays given an object outside the focal point? Select one: a. A b. B c.

Lina20 [59]

Answer:

Answer is C because light travels in a sight line but when light pass through a refractor the light from the source changes direction when passes through a refractor

3 0

2 years ago

Describe the relationship between the wavelength and frequency of electromagnetic waves.

valentina_108 [34]

Answer:

Frequency and wavelength are inversely proportional and the higher the frequency, the higher the energy of the electromagnetic wave.

Explanation:

Electromagnetic waves are transverse waves formed by an electric field and a magnetic field perpendicular to it. They propagate in a vacuum since the variation on an electric field generates a magnetic field and vice versa.

The electromagnetic spectrum is the distribution of radiation due to the different frequencies at which it radiates and its different intensities.

Radiation is distributed along that electromagnetic spectrum according to the wavelength or frequency. For example, X-rays, ultraviolet rays, the visible region are the ones with the highest frequencies and infrared, microwave and radio waves with lower frequencies.

However, the velocity of an electromagnetic wave can be defined as:

$c = \nu \cdot \lambda$ (1)

Where c is the speed of light, $\nu$ is frequency and $\lambda$ is the wavelength.

Therefore, if $\lambda$ or $\nu$ are isolated in equation 1, is easy to see that one is inversely proportional to the other.

$\nu = \frac{c}{\lambda}$ (2)

For example, in equation 2 when the frequency increases the wavelength decreases.

The energy of the electromagnetic wave can be determined by means of the following equation:

$E = h\nu$ (3)

Where h is the Planck's constant and $\nu$ is the frequency.

Hence, frequency and energy are directly proportional.

Equation 2 can be replace in equation 3:

$E = \frac{hc}{\lambda}$ (4)

Then, energy and wavelength are inversely proportional

3 0

4 years ago

Read 2 more answers

Una moto va a 30m/s, transforma en km/h

Alborosie

La moto va a 108 km/h

7 0

4 years ago

(f) As the pions move away from each other, the ratio of the absolute value of electric potential energy to the final total kine

Scorpion4ik [409]

The distance r between the pions when the criteria are satisfied is 1.45 × 10⁻¹⁶ m

If we consider the potential energy (U) between the pions, then (U) can be expressed as:

$\mathbf{U = \dfrac{kq^2}{r} ---- (1)}$

Given that at some instance, the potential energy becomes negligible compared to the final K.E.

As such the conservation of the total energy in the system can be given as:

E = U + K

Again, if we consider the ratio of the potential energy to the kinetic energy to be about 0.01, then:

$\mathbf{\dfrac{U}{K}= 0.01} \\ \\ \mathbf{U = 0.01 K----(2)}$

∴

Equating both equations (1) and (2) together, we have:

$\mathbf{\dfrac{kq^2}{r} = 0.01 K}$

$\mathbf{\dfrac{kq^2}{r} = 0.01 \Bigg [ m_{o \pi}c^2 \Big [\dfrac{1}{\sqrt{1 - \dfrac{v_{\pi}^2}{c^2} }} \Big ] \Bigg] }$

$\mathbf{r =\dfrac{kq^2}{ 0.01 \Bigg [ m_{o \pi}c^2 \Big [\dfrac{1}{\sqrt{1 - \dfrac{v_{\pi}^2}{c^2} }} \Big ] \Bigg] }}$

where:

r = distance
k = Columb's constant
q = charge on a proton
m_o = rest mass of each pion in the previous question
c = velocity of light
$\mathbf{v_\pi}$ = calculated velocity of proton in the previous question

Replacing their values in the above equation, the distance (r) between the pions is calculated as:

$\mathbf{r =\dfrac{(9\times 10^9 \ N.m^2/C^2) (1.6022 \times 10^{-19} \ C)^2}{ 0.01 \Bigg [ (2.5 \times 10^{-28\ kg } )\times (3\times 10^8 \ m/s)^2 \Big [\dfrac{1}{\sqrt{1 - \dfrac{(2.97 \times 10^8 \ m/s)^2}{(3 \times 10^8 \ m/s)^2} }} \Big ] \Bigg] }}$

distance (r) = 1.45 × 10⁻¹⁶ m

Therefore, we can conclude that the distance r between the pions when the criteria are satisfied is 1.45 × 10⁻¹⁶ m

Learn more about electric potential energy here:

brainly.com/question/21808222?referrer=searchResults

3 0

3 years ago