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3 years ago

Ghee freezes from bottom but water freezes from top, why?

1 answer:

8 0

I presume you mean ghee as in the butter. Seen as ice is one of the many solids to have a lower density than its liquid form, it freezes from the top. Ghee is made from hydrocarbons not dissimilar to petroleum, it shares the same properties as most elements of its solid state (at 1 atmosphere) being at a higher density than its liquid state.

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You're at rest in a hammock when a hungry mosquito sees an opportunity for lunch. A mild 2 m/s breeze is blowing. If the mosquit

valentinak56 [21]

Answer:

A) against the breeze at 2 m/s

Explanation:

Given that air is blowing at 2 m/s.An a mosquito eat lunch.If mosquito want to eat lunch he have to move opposite to the direction of air because air is blowing at 2 m/s.So we can say that mosquito have to move against the air.

But in we have to protect our self from mosquito because if any mosquito bite us then it may lead to fever .So the protection is very important from mosquito .

Therefore the answer is --

6 0

3 years ago

How much would a 75kg man weigh due to the effect of gravity

Nezavi [6.7K]

Answer: 735 N

Explanation:

Weight $W$ is a measure of the gravitational force acting on an object and is directly proportional to the product of the mass $m$ of the body by the acceleration of gravity $g$ :

$W=m.g$

In the case of our planet Earth, the acceleration due gravity is $g=9.8 m/s^{2}$ . So for a man whose mass is $m=75 kg$ , his weight is:

$W=(75 kg)(9.8 m/s^{2})$

$W=735 N$

4 0

3 years ago

What is the measurement of loudness of sounds

AURORKA [14]

The measurement of sound is in decibels.

4 0

4 years ago

Suppose a gliding 2-kg cart bumps into, and sticks to, a stationary 5-kg cart. If the speed of the gliding cart before the colli

Thepotemich [5.8K]

Answer:

Therefore,

Final velocity of the coupled carts after the collision is

$v_{f}=4\ m/s$

Explanation:

Given:

Mass of Glidding Cart = m₁ = 2 kg

Mass of Stationary Cart = m₂ = 5 kg

Initial velocity of Glidding Cart = u₁ = 14 m/s

Initial velocity of Stationary Cart = u₂ = 0 m/s

To Find:

Final velocity of the coupled carts after the collision = $v_{f}=?$

Solution:

Law of Conservation of Momentum:

For a collision occurring between two objects in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

It is denoted by "p" and given by

Momentum = p = mass × velocity

Hence by law of Conservation of Momentum we hame

Momentum before collision = Momentum after collision

Here after collision both are stuck together so both will have same final velocity,

$m_{1}\times u_{1}+m_{2}\times u_{2}=(m_{1}+m_{2})\times v_{f}$