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chubhunter [2.5K]
3 years ago
15

Ghee freezes from bottom but water freezes from top, why?

Physics
1 answer:
zhenek [66]3 years ago
8 0
I presume you mean ghee as in the butter. Seen as ice is one of the many solids to have a lower density than its liquid form, it freezes from the top. Ghee is made from hydrocarbons not dissimilar to petroleum, it shares the same properties as most elements of its solid state (at 1 atmosphere) being at a higher density than its liquid state.
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Which of the following best describes the role of culture in the achievement of developmental milestones?
Andrei [34K]

Answer:

Children achieve development milestones at the same time regardless of culture

Explanation:

7 0
3 years ago
Two ice skaters, Lilly and John, face each other while at rest, and then push against each other's hands. The mass of John is tw
seropon [69]

Answer:

Lilly's speed is two times John's speed.

Explanation:

m = Mass

a = Acceleration

t = Time taken

u = Initial velocity

v = Final velocity

The force they apply on each other will be equal

F=ma\\\Rightarrow a_l=\frac{F}{m_l}

F=ma\\\Rightarrow a_j=\frac{F}{2m_l}\\\Rightarrow a_j=\frac{1}{2}a_l

v=u+at\\\Rightarrow v_l=0+\frac{F}{m_l}\times t\\\Rightarrow v_l=a_lt

v=u+at\\\Rightarrow v_l=0+\frac{F}{2m_l}\times t\\\Rightarrow v_j=\frac{1}{2}a_lt\\\Rightarrow v_j=\frac{1}{2}v_l\\\Rightarrow v_l=2v_j

Hence, Lilly's speed is two times John's speed.

4 0
3 years ago
Summary for acceleration. <br><br> HELP PLEASE THIS IS FUE TOMORROW AT 8:00 AM HELP ASAP
viktelen [127]

Answer:

Acceleration is the process in which a object or thing starts gaining speed at a high rate

Explanation:

6 0
3 years ago
The specific gravity of an material is defined as the ratio of the density of the material to the density of water. The specific
Alexandra [31]

The percentage of the iceberg that is visible above the water's surface will be 11.5%.

<h3>What is density?</h3>

Density is defined as the mass per unit volume. It is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.

The mass and density relation is given as

mass = density × volume

Density of ice = 917 kg/m³

Density of the seawater=1025 kg/m³

The ratio by which the iceberg submerge is found as;

\rm  \frac{V_S}{V} =\frac{\rho}{\rho_0} \\\\ \frac{V_S}{V} =\frac{917}{1025} \\\\ \frac{V_S}{V} =.895

Hence,89.5 % of the ice is submerged.

The percentage of the iceberg that is visible above the water's surface is;

⇒1-.89.5 %

⇒11.55 %

Hence, the percentage of the iceberg that is visible above the water's surface will be 11.5%.

To learn more about the density refers to the link;

brainly.com/question/952755

5 0
3 years ago
A trebuchet was a hurling machine built to attack the walls of a castle under siege. A large stone could be hurled against a wal
Studentka2010 [4]

(a) 18.9 m/s

The motion of the stone consists of two independent motions:

- A horizontal motion at constant speed

- A vertical motion with constant acceleration (g=9.8 m/s^2) downward

We can calculate the components of the initial velocity of the stone as it is launched from the ground:

u_x = v_0 cos \theta = (25.0)(cos 41.0^{\circ})=18.9 m/s\\u_y = v_0 sin \theta = (25.0)(sin 41.0^{\circ})=16.4 m/s

The horizontal velocity remains constant, while the vertical velocity changes due to the acceleration along the vertical direction.

When the stone reaches the top of its parabolic path, the vertical velocity has became zero (because it is changing direction): so the speed of the stone is simply equal to the horizontal velocity, therefore

v=18.9 m/s

(b) 22.2 m/s

We can solve this part by analyzing the vertical motion only first. In fact, the vertical velocity at any height h during the motion is given by

v_y^2 - u_y^2 = 2ah (1)

where

u_y = 16.4 m/s is the initial vertical velocity

v_y is the vertical velocity at height h

a=g=-9.8 m/s^2 is the acceleration due to gravity (negative because it is downward)

At the top of the parabolic path, v_y = 0, so we can use the equation to find the maximum height

h_{max} = \frac{-u_y^2}{2a}=\frac{-(16.4)^2}{2(-9.8)}=13.7 m

So, at half of the maximum height,

h = \frac{13.7}{2}=6.9 m

And so we can use again eq(1) to find the vertical velocity at h = 6.9 m:

v_y = \sqrt{u_y^2 + 2ah}=\sqrt{(16.4)^2+2(-9.8)(6.9)}=11.6 m/s

And so, the speed of the stone at half of the maximum height is

v=\sqrt{v_x^2+v_y^2}=\sqrt{18.9^2+11.6^2}=22.2 m/s

(c) 17.4% faster

We said that the speed at the top of the trajectory (part a) is

v_1 = 18.9 m/s

while the speed at half of the maximum height (part b) is

v_2 = 22.2 m/s

So the difference is

\Delta v = v_2 - v_2 = 22.2 - 18.9 = 3.3 m/s

And so, in percentage,

\frac{\Delta v}{v_1} \cdot 100 = \frac{3.3}{18.9}\cdot 100=17.4\%

So, the stone in part (b) is moving 17.4% faster than in part (a).

4 0
4 years ago
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