Answer:
The page field is 8-bit wide, then the page size is 256 bytes.
Using the subdivision above, the first level page table points to 1024 2nd level page tables, each pointing to 256 3rd page tables, each containing 64 pages. The program's address space consists of 1024 pages, thus we need we need 16 third-level page tables. Therefore we need 16 entries in a 2nd level page table, and one entry in the first level page table. Therefore the size is: 1024 entries for the first table, 256 entries for the 2nd level page table, and 16 3rd level page table containing 64 entries each. Assuming 2 bytes per entry, the space required is 1024 * 2 + 256 * 2 (one second-level paget table) + 16 * 64 * 2 (16 third-level page tables) = 4608 bytes.
Answer and Explanation:
Difference between EIRGP and RIP :
- RIP stands for routing information protocol whereas EIRGP stands for enhanced IGRP, IGRP is interior gateway routing protocol
- EGRIP is more based on the link where as RIP is more based on routing
- There is also references in their working operation.
- Differences in updates and refreshing.
Answer:
# include<iostream>
#include<conio.h>
using namespace std;
main()
{
char choice;
cout<<"Enter your Choice"
cin>>choice;
switch (choice)
{
case 'y':
cout<<"Your request is being processed";
break;
case 'n':
cout<<"Thank you anyway for your consideration";
break;
case 'h':
cout<<"Sorry, no help is currently available";
default:
cout<<"Incorrect Choice";
break;
}
getch();
}
Explanation:
In this program, a character type variable named as choice is selected for the input. This choice variable can be y, n or h as per requirement of the program. Switch statement is chose for the selection of output statement with respect to its mentioned input. This program shows the output statement for above mentioned characters. In case of any other character the program returns Incorrect choice and ends.
It does, it has a lot of resources that we can take advantage of. It depends on how you use it
