Use algebra to set up 2 equations.
Assign c as number of tickets for CATS and w for number of tickets of WICKED
c + w = 2700
c / w = 7 / 11
Then solve for one of them in the first equation
c = 2700 - w
Then put this value for c into the 2nd equation
(2700 - w) / w = 7 / 11
Now cross multiply the numerator by denominator of both numerator and denominator pairs
7w = 11 x (2700 - w)
7w = 29700 - 11w
Now solve for w
7w = 26700 - 11w
Add +11w to both sides
18w = 29700
Now divide by 18 on both sides
w = 1650
Then c is the remainder of that ... 2700 - 1650 = 1050
You can also check because 7 / 11 = 1050 / 1650
Answer: 2,4???
Step-by-step explanation:
I feel like it would be 5/12, but im not 100% sure
Answer:
50a^6b^5
Step-by-step explanation:
I don't see answer choices, but this is the simplified version. To do this, multiply 10*5, a^3 * a^3 (which adds the exponents), and then b^3*b^2.
C or B I think
I’m typing random stuff cause it says have 20 characters at least!
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