Answer: If the initial term of an arithmetic sequence is a 1 and the common difference of successive members is d, then the nth term of the sequence is given by: a n = a 1 + (n - 1)d The sum of the first n terms S n of an arithmetic sequence is calculated by the following formula: S n = n (a 1 + a n)/2 = n [2a 1 + (n - 1)d]/2

6 0

2 years ago

Use the square root property of equality to solve (x – 3)2 = –4. The solutions are a. -1 or 7 b. 1 or 5 c. 3+- 2i d. 3+-4i

makkiz [27]

The answer is C. 3+-2i

(x-3) $(x-3)^{2} = -4

 \sqrt{(x-3)^2} = +- \sqrt{-4

x - 3 = i \sqrt{4} 

x - 3 = +-2i

x = 3 +-2i$

6 0

3 years ago

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